24-25 file handling

To open a file c:\test.txt for reading, we should give the statement:

• file1 = open(“c:\test.txt”,”r”)

• file1 = open(“c:\\test.txt”,”r”)

• file1 = open(file=”c:\test.txt”,”r”)

• file1 = open(file=”c:\\s test.txt”,”r”)

To open a file c:\ test.txt for writing, we should use the statement:

• fobj = open(“c:\test.txt”,”w”)

• fobj = open(“c:\\test.txt”,”w”)

• fobj = open(file=”c:\test.txt”,”w”)

• fobj = open(file=”c:\\test.txt”,”w”)

To open a file c:\ test.txt for appending data, we can give the statement:

• fobj = open(“c:\\test.txt”,”a”)

• fobj = open(“c:\\test.txt”,”rw”)

• fobj = open(file=“c:\test.txt”,”w”)

• fobj = open(file=“c:\\ test.txt”,”w”)

Which of the following statements is/are true?

• when we open a file for reading, if the file does not exist, an error occurs.

• when we open a file for writing, if the file does not exist, a new file is created.

• when we open a file for writing, if the file exists, the existing file is overwritten with the new file.

• All of these

Identify the error in the following code.

1. 1. f = open ("workfile.txt', 'r+')

2. f.write('0123456789abcdef')

3. f.write('xyz8466')

4. f.close()

5. f.seek (0)

6. f.read()

• Line 1

• Line 2

• Line 5

• Line 6

To read the entire contents of the file as a string from a file object fobj, the command should be:

• fobj.read(2)

• fobj.read()

• fobj.readline()

• fobj.readlines()

What will be the output of the following snippet?

• True

• False

• None

• Error

To read the next line of the file from a file object fobj, we use:

• fobj.read(2)

• fobj.read()

• fobj.readline()

• fobj.readlines()

To read the remaining lines of the file from object fobj, we use:

• fobj.read(2)

• fobj.read()

• fobj.readline()

• fobj.readlines()

The readlines() method returns:

• String

• A list of integers

• A list of single characters

• A list of strings