Solving multi-step problems using non-linear inequalities in one variable

What is the solution set to x² - 16 ≤ 0

• (-∞, -4) υ (4, ∞)

• (-4, 4)

• [-4, 4]

• (-∞, -4] υ [4, ∞)

• 
• 
• 
• 

Which of these is a solution to the following quadratic inequality: y > x² - 6x + 2

• ( 0 , 2 )

• ( 2, 0 )

• ( -2, 0)

• ( 0, -2)

What is the solution set?

2x² -3x+1 > 0

• $\left(-\infty,\ \frac{1}{2}\right)\cup\left(1,\ \infty\right)$

• $\left(\frac{1}{2},\ 1\right)$

• $\left[\frac{1}{2},\ 1\right]$

• $\left(-\infty,\ \frac{1}{2}\right]\cup\left[1,\ \infty\right)$

 $x^2-4x+3\ge0$  

•  $x<1$  or  $x>3$  

•  $1\le x\le3$  

•  $-3\le x\le-1$  

•  $x\le1$  or  $x\ge3$  

Which is the solution set of  $x^2-8x+14<0$ ?

•  $\left[4-\sqrt{2},4+\sqrt{2}\right]$  

•  $\left(4-\sqrt{2},4+\sqrt{2}\right)$  

•  $\left(-\infty,4-\sqrt{2}\right)\cup\left(4+\sqrt{2},\infty\right)$  

•  $\left(-\infty,4-\sqrt{2}\right]\cup\left[4+\sqrt{2},\infty\right)$  

In solving word problems involving quadratic inequalities what is the translation of the keyword “no less than”?

• $\ge$

• $\le$

• >

• <

The value of p for equation 2x² – 4x + p = 0 to have real roots will be....

• p ≤ –2

• p ≥ 2

• p ≤ 2

• p ≥ –2

Solve the inequality:

 $x^2+11x+30>0$  

•  $\left(-6,-5\right)$  

•  $\left(-\infty-6\right)\left(-5,\infty\right)$  

•  $\left(5,6\right)$  

•  $\left(-\infty,5\right)\left(6,\infty\right)$