Writing the equation of a straight line

Write the equation of a line in slope intercept form.

m = 3

( 3, 9 )

(a)  

Find the y-intercept of the line that passes through the point (6,8) with slope m=4.

• b = −16

• b = 26

• b = 16

• b = −26

Write the equation of the line with a slope of -3 and passing through the point (5,4)

Write the equation in POINT-SLOPE form of the line that passes through point  

(-2, -1) and has a slope of m= -3.

• y - 1 = -3(x - 2)

• y + 1 = -3(x + 2)
• y - 2 = 3(x - 1)

• y + 2 = -3(x + 1)

Write the equation of a line with m = 3 that passes through (2, -1)

• y = 3x + 1

• Y = 3x - 7

• y = -3x + 5

Write the slope-intercept form of the equation with the given point and slope.

Through ( 1, 5 ) and m = 3

• y = 3x + 2

• y = 3x - 2

• y = 2x + 3

Write the equation of the line with slope -2 through the point (7, -1).

• y = -2x + 15
• y = -2x -15
• y = -2x + 13
• y = -2x - 13

Write the equation in POINT-SLOPE form of the line that passes through the point (7, -4) and has a slope of -1/4,

• y +4 = -1/4(x - 7)

• y - 4 = -1/4(x + 7)
• y + 7 = -1/4(x - 4)

• y - 7 = -1/4(x + 4)

Write the equation of the line in slope intercept form.

(Do NOT put any spaces in your answer.)

(a)  

 $y=-\frac{2}{3}x-\frac{1}{3}$  

•  $m=\frac{1}{3};\ y=\left(0,-\frac{2}{3}\right)$  

•  $m=-\frac{2}{3};\ y=\left(\frac{1}{3},0\right)$  

•  $m=-\frac{2}{3};\ y=\left(0,\frac{1}{3}\right)$  

•  $m=0;\ y=\left(\frac{2}{3},\frac{1}{3}\right)$