Math Test 1
Quiz
•
Mathematics
•
10th Grade
•
Practice Problem
•
Medium
+7
Standards-aligned
Angel Cartagena
Used 3+ times
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16 questions
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1.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Answer explanation
To simplify \( \sqrt{147} \), we factor it as \( \sqrt{49 \cdot 3} = \sqrt{49} \cdot \sqrt{3} = 7\sqrt{3} \). Thus, the correct answer is \( 7\sqrt{3} \).
Tags
CCSS.HSN.RN.A.2
2.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Tags
CCSS.HSN.RN.A.2
3.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Answer explanation
To simplify \( \sqrt[3]{108} \), we factor 108 as \( 108 = 27 \times 4 \). Thus, \( \sqrt[3]{108} = \sqrt[3]{27 \times 4} = \sqrt[3]{27} \cdot \sqrt[3]{4} = 3 \sqrt[3]{4} \). Therefore, the correct answer is \( 3\sqrt[3]{4} \).
Tags
CCSS.8.EE.A.2
4.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Simplify:
2√6 + 5√6
7√6
6√7
7√12
10√6
Answer explanation
To simplify 2√6 + 5√6, combine the coefficients of √6: (2 + 5)√6 = 7√6. Thus, the correct answer is 7√6.
Tags
CCSS.HSA.SSE.B.3
CCSS.HSN.RN.A.2
5.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Simplify:
√3 + √27
4√3
3√3
2√3
Cannot be added.
Answer explanation
To simplify √3 + √27, first simplify √27 to 3√3. Then, √3 + 3√3 = 4√3. Thus, the correct answer is 4√3.
Tags
CCSS.HSA.SSE.B.3
CCSS.HSN.RN.A.2
6.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
What is the midpoint of AB given A(2, 3) and B(8, 7)
(5, 5)
(6, 5)
(5, 7)
(4, 4)
Answer explanation
To find the center of MN, use the midpoint formula: ((x1+x2)/2, (y1+y2)/2). For M(3, -1) and N(7, -5), the center is ((3+7)/2, (-1-5)/2) = (5, -3). Thus, the correct answer is (5, -3).
Tags
CCSS.HSG.GPE.B.6
7.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
The midpoint M and one endpoint of segment GH is given. Find the coordinates of the other endpoint. G(5, -6) and M(4,3).
(3, 12)
(6, 4)
(1, 2)
Answer explanation
To find the other endpoint H, use the midpoint formula: M = ((Gx + Hx)/2, (Gy + Hy)/2). Given G(5, -6) and M(4, 3), solve for H. This gives H(3, 12), which matches the correct answer.
Tags
CCSS.HSG.GPE.B.6
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