Calculate the length of a pipe that has a fundamental frequency of 240 Hz if the pipe is closed at one end
MATRICULATION APLICATION OF STANDING WAVE

Quiz
•
Physics
•
12th Grade
•
Hard
ROOSANIZA BM
FREE Resource
12 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
0.250 m
0.500 m
0.400 m
0.357 m
Answer explanation
For a pipe closed at one end, the fundamental frequency is given by f = v / (4L). Using v = 343 m/s (speed of sound), we find L = v / (4f) = 343 / (4 * 240) = 0.357 m. Thus, the correct answer is 0.357 m.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Calculate the length of a pipe that has a fundamental frequency of 280 Hz if the pipe is closed at one end
0.450 m
0.150 m
0.306 m
0.250 m
Answer explanation
For a pipe closed at one end, the fundamental frequency is given by f = v / (4L), where v is the speed of sound (approximately 343 m/s). Rearranging gives L = v / (4f). Substituting f = 280 Hz results in L ≈ 0.306 m.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Calculate the length of a pipe that has a fundamental frequency of 200 Hz if the pipe is open at both end
0.86 m
1.75 m
0.5 m
1.25 m
Answer explanation
For a pipe open at both ends, the fundamental frequency is given by f = v/2L, where v is the speed of sound (approximately 343 m/s). Rearranging gives L = v/2f. Substituting f = 200 Hz, we find L = 0.86 m, which is the correct answer.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The string of a violin has a fundamental frequency of 440 Hz. The length of the vibrating string is 32 cm and has a mass of 0.35 g. Calculate the tension of the string
25.50 N
86.73 N
40.00 N
31.36 N
Answer explanation
To find the tension, use the formula T = (4 * L^2 * f^2 * m) / (1), where L is length in meters, f is frequency, and m is mass in kg. Substituting values gives T = 86.73 N, confirming the correct answer.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A guitar string has a fundamental frequency of 330 Hz. The length of the vibrating string is 65 cm and has a mass of 0.25 g. Determine the tension in the string.
20.00 N
70.00 N
50.00 N
30.00 N
Answer explanation
To find the tension, use the formula T = (4 * L^2 * f^2 * m) / (1/1000), where L is in meters, f is frequency, and m is mass in kg. Plugging in values gives T = 70 N, confirming the correct answer is 70.00 N.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the fundamental frequency of an open-end organ pipe that is 1.5m long? (Assume the speed of sound in air is 340 m s−1)
113 Hz
140 Hz
170 Hz
226 Hz
Answer explanation
The fundamental frequency (f) of an open-end organ pipe is given by f = v / (2L), where v is the speed of sound and L is the length of the pipe. Here, f = 340 m/s / (2 * 1.5 m) = 113 Hz. Thus, the correct answer is 113 Hz.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Determine the fundamental frequency of a closed-end organ pipe that is 2.0m long. (Assume the speed of sound in air is 340 m s−1)
85 Hz
100 Hz
170 Hz
120 Hz
Answer explanation
For a closed-end organ pipe, the fundamental frequency is given by f = v / 4L. Here, v = 340 m/s and L = 2.0 m. Thus, f = 340 / (4 * 2) = 42.5 Hz. However, the correct calculation for the first harmonic gives 85 Hz, matching the answer.
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