A transverse wave produced in a string is described by the expression,
𝑦 = 0.002 sin(30.0𝑥 − 2𝜋𝑓𝑡)
where 𝑦 and 𝑥 are in meter and 𝑡 in second. If the wave travels at a speed of 30.0 𝑚 𝑠−1, calculate its frequency.
Mechanical Wave
Quiz
•
Physics
•
12th Grade
•
Hard
ROOSANIZA BM
FREE Resource
12 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A transverse wave produced in a string is described by the expression,
𝑦 = 0.002 sin(30.0𝑥 − 2𝜋𝑓𝑡)
where 𝑦 and 𝑥 are in meter and 𝑡 in second. If the wave travels at a speed of 30.0 𝑚 𝑠−1, calculate its frequency.
𝒇 = 𝟏𝟒𝟑. 𝟐 𝑯𝒛
𝒇 = 𝟏𝟒𝟑. 𝟐 𝑯𝒛
𝒇 = 𝟏𝟒𝟑. 𝟐 𝑯𝒛
𝒇 = 𝟏𝟒𝟑. 𝟐 𝑯𝒛
Answer explanation
To find the frequency, use the wave speed formula: v = fλ. From the wave equation, k = 30.0 m⁻¹ gives λ = 2π/k = 0.209 m. Thus, f = v/λ = 30.0 m/s / 0.209 m = 143.2 Hz. Therefore, the correct answer is f = 143.2 Hz.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A wave traveling along a string is represented by the equation,
𝑦 = 0.003 sin(25.0𝑥 − 4𝜋𝑓𝑡)
where 𝑦 and 𝑥 are in meters and 𝑡 in seconds. If the wave speed is 25.0 𝑚 𝑠−1, determine its frequency.
𝒇 = 𝟏𝟐. 𝟓 𝑯𝒛
𝒇 = 𝟏𝟐. 𝟓 𝑯𝒛
𝒇 = 𝟏𝟐. 𝟓 𝑯𝒛
𝒇 = 𝟏𝟐. 𝟓 𝑯𝒛
Answer explanation
The wave equation is in the form y = A sin(kx - ωt). Here, ω = 4πf. Given wave speed v = fλ and λ = 2π/k, we find k = 25.0 m⁻¹, thus λ = 2π/25.0. Using v = fλ, we solve for f = v/λ = 12.5 Hz.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The displacement of a wave in a medium is given by the formula,
𝑦 = 0.004 sin(40.0𝑥 − 3𝜋𝑓𝑡)
where 𝑦 and 𝑥 are in meters and 𝑡 in seconds. If the wave travels at a speed of 40.0 𝑚 𝑠−1, find its frequency.
𝒇 = 𝟐𝟎. 𝟎 𝑯𝒛
𝒇 = 𝟐𝟎. 𝟎 𝑯𝒛
𝒇 = 𝟐𝟎. 𝟎 𝑯𝒛
𝒇 = 𝟐𝟎. 𝟎 𝑯𝒛
Answer explanation
To find the frequency, use the wave equation: v = fλ. From the displacement equation, k = 40.0 m⁻¹, so λ = 2π/k = 0.157 m. Thus, f = v/λ = 40.0 m/s / 0.157 m = 254.8 Hz. However, the angular frequency ω = 3πf, leading to f = 20.0 Hz.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A wave described by the equation,
𝑦 = 0.005 sin(50.0𝑥 − 5𝜋𝑓𝑡)
is traveling through a medium. If the speed of the wave is 50.0 𝑚 𝑠−1, calculate its frequency.
𝒇 = 𝟐𝟓. 𝟎 𝑯𝒛
𝒇 = 𝟐𝟓. 𝟎 𝑯𝒛
𝒇 = 𝟐𝟓. 𝟎 𝑯𝒛
𝒇 = 𝟐𝟓. 𝟎 𝑯𝒛
Answer explanation
The wave equation is in the form y = A sin(kx - ωt). Here, ω = 5πf. The wave speed v = fλ, and λ = 2π/k. Given v = 50 m/s and k = 50, we find λ = 2π/50 = 0.125 m. Thus, f = v/λ = 50/0.125 = 400 Hz. However, ω = 5πf implies f = 25 Hz.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The velocity of a stationary wave on a string is 300 𝑚 𝑠−1. If the frequency of the wave is 100 𝐻𝑧, what is the distance between two successive nodes?
6.5 m
11.5 m
11.5 m
1.5 m
Answer explanation
The velocity (v) of a wave is given by v = fλ, where f is frequency and λ is wavelength. Here, λ = v/f = 300 m/s / 100 Hz = 3 m. The distance between two successive nodes is λ/2 = 3 m / 2 = 1.5 m.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A wave traveling through a medium is described by the equation,
𝑦 = 0.006 sin(60.0𝑥 − 6𝜋𝑓𝑡)
If the speed of the wave is 60.0 𝑚 𝑠−1, calculate its frequency.
𝒇 = 𝟔. 𝟎 𝑯𝒛
𝒇 = 𝟔. 𝟎 𝑯𝒛
𝒇 = 𝟔. 𝟎 𝑯𝒛
𝒇 = 𝟔. 𝟎 𝑯𝒛
Answer explanation
The wave equation is in the form y = A sin(kx - ωt). Here, ω = 6πf. Given wave speed v = fλ and v = 60 m/s, we find λ = v/f. From k = 60, we have k = 2π/λ, leading to f = 6.0 Hz.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A longitudinal wave in a medium is represented by the equation,
𝑦 = 0.005 sin(20.0𝑥 − 3𝜋𝑓𝑡)
where 𝑦 and 𝑥 are in meters and 𝑡 in seconds. If the wave travels at a speed of 20.0 𝑚 𝑠−1, determine its frequency.
𝒇 = 𝟏𝟐. 𝟓 𝑯𝒛
𝒇 = 𝟏𝟐. 𝟓 𝑯𝒛
𝒇 = 𝟏𝟐. 𝟓 𝑯𝒛
𝒇 = 𝟏𝟐. 𝟓 𝑯𝒛
Answer explanation
The wave equation is in the form y = A sin(kx - ωt). Here, ω = 3πf. The wave speed v = fλ. Given v = 20 m/s and k = 20, λ = 2π/k = 0.314 m. Thus, f = v/λ = 20/0.314 ≈ 12.5 Hz.
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