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10 Qs

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Assessment

Quiz

Computers

University

Hard

Created by

Gouthami Velakanti

Used 2+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Which of the following data structure can provide efficient searching of the elements?

a) unordered lists

b) binary search tree

c) tree

d) 2-3 tree

2.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Consider a B+-tree in which the maximum number of keys in a node is 5. What is the minimum number of keys in any non-root node? (GATE CS 2010)

4

3

2

1

3.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Consider a B+-tree in which the maximum number of keys in a node is 5. What is the minimum number of keys in any non-root node? (GATE CS 2010)

a) logn (k+1) – 1

b) nk

c) logk (n+1) – 1

d) klogn

4.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Which of the following is true?

a) larger the order of B-tree, less frequently the split occurs

b) larger the order of B-tree, more frequently the split occurs

c) smaller the order of B-tree, more frequently the split occurs

d) smaller the order of B-tree, less frequently the split occurs

5.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

What is the special property of red-black trees and what root should always be?

a) a color which is either red or black and root should always be black color only

b) height of the tree

c) pointer to next node

d) a color which is either green or black

6.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Which of the following is an application of Red-black trees and why?

a) used to store strings efficiently

b) used to store integers efficiently

c) can be used in process schedulers, maps, sets

d) for efficient sorting

7.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

What is the below pseudo code trying to do, where pt is a node pointer and root pointer?

redblack(Node root, Node pt) :

if (root == NULL)

return pt  

if (pt.data < root.data)

{

root.left = redblack(root.left, pt); root.left.parent = root }

else if (pt.data > root.data)

{ root.right = redblackt(root.right, pt)

root.right.parent = root }

return root

a) insert a new node

b) delete a node

c) search a node

d) count the number of nodes

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