Exploring Parametric Equations: Beginnings Part 2

Exploring Parametric Equations: Beginnings Part 2

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

CCSS
HSG.GPE.A.1, HSA.CED.A.4, HSA.REI.B.3

Standards-aligned

Created by

Mia Campbell

FREE Resource

Standards-aligned

CCSS.HSG.GPE.A.1
,
CCSS.HSA.CED.A.4
,
CCSS.HSA.REI.B.3
The video tutorial covers the basics of parametric equations, including how to eliminate parameters using trigonometric identities and algebra. It provides examples of converting parametric equations to standard forms, such as circles and parabolas, and demonstrates methods to create parametric equations from standard equations. The tutorial concludes with a brief mention of further calculus topics.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the radius of the circle derived from the parametric equations x = 2 cos(θ) and y = 2 sin(θ)?

2

1

4

3

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which trigonometric identity is used to eliminate the parameter in the equations x = 2 cos(θ) and y = 2 sin(θ)?

sin(2θ) = 2 sin(θ) cos(θ)

1 / cos(θ) = sec(θ)

sin(θ) / cos(θ) = tan(θ)

sin^2(θ) + cos^2(θ) = 1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the standard form equation derived from x = 2 cos(θ) and y = 2 sin(θ)?

x^2 + y^2 = 2

x^2 - y^2 = 2

x^2 - y^2 = 4

x^2 + y^2 = 4

Tags

CCSS.HSG.GPE.A.1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the equation x^2 + y^2 = 4 represent?

An ellipse

A parabola

A hyperbola

A circle

Tags

CCSS.HSG.GPE.A.1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you solve for 't' from the equation x = 3/2 t?

t = 3/2x

t = x/3

t = 3x/2

t = 2x/3

Tags

CCSS.HSA.CED.A.4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the resulting equation for y when substituting t = 2/3 x into y = 4 - 3/4 t^2?

y = 4 - 1/3 x^2

y = 4 + 3/2 x^2

y = 4 + 1/3 x^2

y = 4 - 3/2 x^2

Tags

CCSS.HSA.REI.B.3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the simplest form of parametric equations for y = 6x^2 - 1?

x = t, y = 6t^2 - 1

x = t^2, y = 6t - 1

x = t, y = 6t - 1

x = t^2, y = 6t^2 - 1

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