Quiz matematika aljabar
Quiz
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Others
•
6th - 8th Grade
•
Hard

Rhodrigez Glensen
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15 questions
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1.
FILL IN THE BLANK QUESTION
1 min • 20 pts
jika x+y=2,y+z=4,dan x+z=6,tentukan nilai dari x+y+z.(Soal HOTS)
Answer explanation
Nah,disoal tersebut ada 3 SPLDV
Yang pertama itu x+y=2
Yang kedua itu y+z=4
Yang ketiga itu x+z=6
Untuk soal ini,tidak perlu mencari satu per satu
Tinggal tambahkan semua persamaan tersebut,maka akan jadi:
2x+2y+2z=12
2(x+y+z)=12
2:2(x+y+z)=12:2 {kedua ruas dibagi dengan 2}
x+y+z=6
2.
MULTIPLE CHOICE QUESTION
30 sec • 10 pts
a⁵ × a³ ÷ a⁴ x a⁷=
a¹¹
a¹²
a⁹
a⁸
Answer explanation
a⁵ × a³ ÷ a⁴ × a⁷=
Kita memakai dua sifat eksponen yaitu:
1.a^m x a^n=a^m+n
Contoh:a²×a³=a^2+3=a⁵
2.a^m ÷a^n=a^m-n
Contoh:a⁴÷a²=a^4-2=a²
Balik lagi ke penyelesaian soal ini berarti bisa diubah menjadi:
a^5+3-4+7=a¹¹
3.
MULTIPLE CHOICE QUESTION
30 sec • 10 pts
Jika x+y=2 dan 2x+y=4,temukan nilai dari x
2
1
3
0
Answer explanation
X+y=2 dan 2x+y=4,untuk mengerjakan soal ini tinggal eliminasi y:
X+y=2
2x+y=4
______-
-x=-2
-x × -1=-2 ×-1
X=2
4.
FILL IN THE BLANK QUESTION
1 min • 1 pt
6³×2³=
Answer explanation
6³×2³=
Pada soal ini kita bisa menggunakan sifat
(Ab)^m=a^m × b^m
Berarti 6³×2³=12³/12^3
5.
FILL IN THE BLANK QUESTION
1 min • 20 pts
Tentukan nilai dari x²+2x+7,jika x+2=7.{soal HOTS}
Answer explanation
Nilai dari x²+2x+7,jika x+2=7 adalah:
X²+2x bisa kita ubah ke bentuk distributif,yaitu:
X(x+2)
Lalu kita tulis lagi menjadi
X(x+2)+7
Karna nilai x+2=7,berarti x=5,kita bisa substitusikan menjadi:
5(7)+7=42
6.
FILL IN THE BLANK QUESTION
1 min • 8 pts
Ubah 5a³+10a² ke bentuk distributif
Answer explanation
Ubah 5a³+10a² ke bentuk distributif:
5a³ dan 10a² sama sama mengandung 5a²
Berarti bentuk distributifnya adalah:
5a²(a+2)
7.
FILL IN THE BLANK QUESTION
1 min • 1 pt
Jika x+1=9,temukan x
Answer explanation
X+1=9
X=?
Penyelesaian:
X+1=9
X+1-1=9-1
X=8
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