Compound Interest Loans and Investments

Compound Interest Loans and Investments

12th Grade

18 Qs

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Compound Interest Loans and Investments

Compound Interest Loans and Investments

Assessment

Quiz

Mathematics

12th Grade

Practice Problem

Hard

Created by

Jo ONeill

Used 4+ times

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18 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt


$450 is invested in an account paying a compound interest rate of 3.75%  p.a. The recurrence relation for the value of the investment after 𝑛 years is

An+1=1.0375 A0=450

An+1=450+An, A0=450

An+1=450+d A0=450

Answer explanation

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2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt


$2200 is invested at 5.5% p.a. compounded yearly. The amount of interest earned on the investment after 48 months, correct to the nearest cent, is

484

525.41

539.99

26 543.57

Answer explanation

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3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the difference in money terms between investing  $100000 at 10% p.a. for 5 years compounded yearly as compared to compounded monthly? (Give the closest answer.)

$3000

$3500

$4000

$4500

Answer explanation

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4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The number of interest-bearing periods for an investment that is compounded quarterly over 5 years is

5

60

59

20

Answer explanation

Four quarters per year over five years, thus 20 periods.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The future value, correct to the nearest cent, of $15 000 invested at 5.25% p.a. compounded monthly for 5 years is

$15 331.01

$18 937.50

$19 373.22

$19 491.48

Answer explanation

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6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

An investment of $1230 was made over 5 years at an interest rate of 6% p.a. with interest compounding annually. The interest earned during the second year is

$1382.03

$147.60

$73.80

$78.23

Answer explanation

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7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Katya deposits $1000 into an account that adds 0.5% interest at the end of each month. Let 𝑀𝑛 be the money in the account at the end of month 𝑛. A first-order recurrence relation that would describe this situation is

Mn+1 = 1.005Mn, M0 = 1000

Mn+1 = 1.05Mn, M1 = 1000

Mn+1 = Mn+50, M0 = 1000

Mn+1 = 1.005Mn, +1000 M0

Answer explanation

Media Image

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