AAT Mat Kelas 8

The function formula for f (1) = 3 and f (2) = 5 is….

• f(x) = 4x + 1

• f(x) = 2x – 6

• f(x) = 2x + 2

• f(x) = 2x – 2

Given the original region {–2, –1, 0, 1, 2), the resulting region of the function formula f(x) = 4x + 2 is….

• –6, –2, 2, 6, 10

• –6, 4, 6, 10, 12

• –4, –2, 3, 6, 9

• –6, –3, 6, 10

The value a of f (2) = – 6 and f (3) = –5 is….

• –4

• –2

• 1

• 2

The b values of f (1) = 2 and f (2) = 1 is….

• 3

• 9

• 12

• 15

A mapping is expressed in the form R = {(2,a), (4,b), (6,a), (8,b)}. The range is….

• {a}

• {a, b}

• {2, 4, 6, 8}

• {2, 4, 6}

It's known that the function formula f(x) = 2x + 2. The value of f (4) is….

• 4

• 6

• 10

• 12

Look at the following mapping arrow diagram!

The mapping range is….

• {a, b, c, d, e}

• {a, b, c}

• {1, 2, 3}

• {1, 2, 3, 4}

Given the set of ordered pairs {(1,1), (2,4), (3,9), (4,16)}. Which is the domain of the set is….

• {1, 2, 3, 4, 9, 16}

• {1, 4, 9, 16}

• {1, 2, 4, 9}

• {1, 2, 3, 4}

The equation of the line that passes through the point (–4,3) and has a gradient of  –2 is….

• y = –2x – 5

• y = 2x + 5

• y = 2x + 4

• x + 2y + 1 = 0

The equation of the line that passes through the point (6,0) and (0, –2) is….

• –y = x + 4

• y = –2x + 2

• –6y = –2x + 12

• 2y = 4x – 7