Molarity (without stoich)

How many liters would you need to make a 1 M solution if you have 6 mol of Sodium Hydroxide? 

• 2

• 3

• 4

• 6 

Answer explanation

To make a 1 M solution with 6 mol of Sodium Hydroxide, you would need 6 liters of the solution.

What is the molarity of 4 g of NaCl (MM=58.45) in 3,800 mL of solution?

• 0.018 M

• 0.0011 M

• 1.052 M

• 0.062 M

Answer explanation

To find the molarity, first calculate the moles of NaCl: 4g / 58.45 g/mol = 0.0684 mol. Then, divide moles by liters: 0.0684 mol / 3.8 L = 0.018 M.

Find the molarity of 186.55 g of sucrose, C₁₂H₂₂O₁₁ (MM = 342) in 250 mL of water.

• 2.18 M

• 0.746 M

• 1.18 M

• 0.545 M

Answer explanation

The molarity is calculated by dividing the moles of sucrose by the volume in liters. Moles = 186.55g / 342g/mol = 0.545 mol. Molarity = 0.545 mol / 0.25 L = 2.18 M.

How many grams of AgNO₃ (MM = 169.87) are needed to prepare 0.125M solution in 250 mL of water? 

• .03g

• 0.5g

• 5.3g

• 84.9g

Answer explanation

To calculate the grams needed, use the formula: grams = Molarity x Volume x Molar Mass. Substituting the values, grams = 0.125 x 0.25 x 169.87 = 5.3g. Therefore, 5.3g of AgNO3 are needed to prepare the solution.

Calculate the molarity of the following solution:  1.0 mole of KCl in 750.0 mL of solution.

• 0.750 M

• 99 M

• 1.3 M

• 2.0 M

Answer explanation

The molarity is calculated by dividing moles of solute by liters of solution. In this case, 1.0 mole of KCl in 750.0 mL (0.75 L) gives a molarity of 1.3 M

What is the molarity of a solution made by adding 1.565 moles of PbNO₃ to 500 mL?

• 300. M

• 31.3 M

• 3.13 M

• 1.56 M

Answer explanation

To find the molarity, divide the moles of solute by the volume of solution in liters. 1.565 moles / 0.5 L = 3.13 M.

How many L are required to make 3.5 M hydrochloric acid using 1.1 moles? 

• 3.18 L

• 0.31 L

• 3.85 L

• 4.6 L

Answer explanation

To make 3.5 M HCl with 1.1 moles, divide moles by concentration: 1.1 moles / 3.5 M = 0.31 L required.

What is the formula for molarity?

• moles/grams

• moles/kilograms

• moles/milliliters

• moles/liters

Answer explanation

The formula for molarity is moles/liters. This ratio represents the number of moles of solute dissolved in one liter of solution.

Tags

NGSS.HS-PS1-5

If you have 0.045 L of 0.465 M potassium bromide. How many moles of potassium bromide are present?

• 20.9 mol

• 0.021 mol

• 0.02 mol

• 0.0209 mol

Answer explanation

To find the moles of potassium bromide, use the formula Moles = Volume (L) x Concentration (M). Moles = 0.045 L x 0.465 M = 0.0209 mol. Therefore, 0.0209 mol of potassium bromide are present.

Determine the molarity of 0.444 mol of CoCl₂ in 0.654 L of solution

• 0.679 M

• 12 M

• 0.6 M

• 6 M

Answer explanation

To find molarity, divide moles of solute by liters of solution. Molarity = 0.444 mol / 0.654 L = 0.679 M. Therefore, the correct choice is 0.679 M.