Molarity (without stoich)

Molarity (without stoich)

10th Grade

13 Qs

quiz-placeholder

Similar activities

คำถามสายรหัส

คำถามสายรหัส

10th Grade

15 Qs

soalan pengukuhan bab 8

soalan pengukuhan bab 8

6th - 12th Grade

10 Qs

Physics  = Pressure Level 1

Physics = Pressure Level 1

10th - 11th Grade

10 Qs

Calculs concentration

Calculs concentration

10th Grade

10 Qs

AYO BELAJAR RANGKAIAN LISTRIK

AYO BELAJAR RANGKAIAN LISTRIK

1st - 10th Grade

10 Qs

Evaluación Semanal 1.

Evaluación Semanal 1.

10th - 12th Grade

16 Qs

Prueba Objetiva de Ciencias Naturales. Primer Periodo

Prueba Objetiva de Ciencias Naturales. Primer Periodo

10th Grade

10 Qs

Bidang Miring

Bidang Miring

8th - 11th Grade

10 Qs

Molarity (without stoich)

Molarity (without stoich)

Assessment

Quiz

Science

10th Grade

Medium

NGSS
HS-PS1-5

Standards-aligned

Created by

Samina syed

Used 2+ times

FREE Resource

AI

Enhance your content in a minute

Add similar questions
Adjust reading levels
Convert to real-world scenario
Translate activity
More...

13 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

How many liters would you need to make a 1 M solution if you have 6 mol of Sodium Hydroxide? 

2

3

4

Answer explanation

To make a 1 M solution with 6 mol of Sodium Hydroxide, you would need 6 liters of the solution.

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What is the molarity of 4 g of NaCl (MM=58.45) in 3,800 mL of solution?

0.018 M

0.0011 M

1.052 M

0.062 M

Answer explanation

To find the molarity, first calculate the moles of NaCl: 4g / 58.45 g/mol = 0.0684 mol. Then, divide moles by liters: 0.0684 mol / 3.8 L = 0.018 M.

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Find the molarity of 186.55 g of sucrose, C12H22O11 (MM = 342) in 250 mL of water.

2.18 M

0.746 M

1.18 M

0.545 M

Answer explanation

The molarity is calculated by dividing the moles of sucrose by the volume in liters. Moles = 186.55g / 342g/mol = 0.545 mol. Molarity = 0.545 mol / 0.25 L = 2.18 M.

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

How many grams of AgNO3 (MM = 169.87) are needed to prepare 0.125M solution in 250 mL of water? 

.03g

0.5g

5.3g

84.9g

Answer explanation

To calculate the grams needed, use the formula: grams = Molarity x Volume x Molar Mass. Substituting the values, grams = 0.125 x 0.25 x 169.87 = 5.3g. Therefore, 5.3g of AgNO3 are needed to prepare the solution.

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Calculate the molarity of the following solution:  1.0 mole of KCl in 750.0 mL of solution.

0.750 M

99 M

1.3 M

2.0 M

Answer explanation

The molarity is calculated by dividing moles of solute by liters of solution. In this case, 1.0 mole of KCl in 750.0 mL (0.75 L) gives a molarity of 1.3 M

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

What is the molarity of a solution made by adding 1.565 moles of PbNO3 to 500 mL?

300. M

31.3 M

3.13 M

1.56 M

Answer explanation

To find the molarity, divide the moles of solute by the volume of solution in liters. 1.565 moles / 0.5 L = 3.13 M.

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

How many L are required to make 3.5 M hydrochloric acid using 1.1 moles? 

3.18 L

0.31 L

3.85 L

4.6 L

Answer explanation

To make 3.5 M HCl with 1.1 moles, divide moles by concentration: 1.1 moles / 3.5 M = 0.31 L required.

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?