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Avogadro's Number and the Mole Review

Authored by Dorvera Owens

Chemistry

10th Grade

NGSS covered

Used 12+ times

Avogadro's Number and the Mole Review
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13 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

How much is one mole?

6.02 x 1023

3 x 108

6.67 x 10-11

6.63 x 10-34

Answer explanation

One mole is equal to Avogadro's number, which is approximately 6.02 x 10^23. This is the correct choice for the amount in one mole.

Tags

112.35.c.8.B

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many particles are there in 0.250 mol of Ag?

1.505 x 10^23 particles Ag

6.02 x 10^23 particles Ag

3.01 x 10^23 particles Ag

1.204 x 10^24 particles Ag

Answer explanation

0.250 mol of Ag contains 1.505 x 10^23 particles of Ag, as 1 mol of Ag contains 6.02 x 10^23 particles.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many particles are there in 0.00858 mol NaCl?

5.16 x 10^21 particles NaCl

5.15 x 10^21 particles NaCl

5.15 x 10^22 particles NaCl

5.15 x 10^20 particles NaCl

Answer explanation

0.00858 mol NaCl x 6.022 x 10^23 particles/mol = 5.15 x 10^21 particles NaCl

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many particles are there in 35.4 mol of CO2?

2.13 x 10^23 particles CO2

2.13 x 10^24 particles CO2

2.13 x 10^25 particles CO2

2.13 x 10^22 particles CO2

Answer explanation

To find the number of particles in 35.4 mol of CO2, use Avogadro's number (6.022 x 10^23 particles/mol) and multiply by the given amount: 35.4 mol * 6.022 x 10^23 particles/mol = 2.13 x 10^24 particles CO2.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many particles are there in 0.425 kmol of N2?

2.56 x 10^23 particles N2

2.56 x 10^24 particles N2

2.56 x 10^25 particles N2

2.56 x 10^26 particles N2

Answer explanation

0.425 kmol of N2 contains 0.425 x 6.022 x 10^23 particles = 2.56 x 10^23 particles N2

Tags

NGSS.HS-PS1-7

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many moles of Pb are there in 3.25 x 10^20 atoms of Pb?

5.40 x 10^-4 mol Pb

5.40 x 10^-3 mol Pb

5.40 x 10^-5 mol Pb

5.40 x 10^-6 mol Pb

Answer explanation

To find the number of moles, divide the number of atoms by Avogadro's number (6.022 x 10^23). 3.25 x 10^20 / 6.022 x 10^23 = 5.40 x 10^-4 mol Pb.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many moles of glucose (C6H12O6) are there in 4.96 x 10^24 molecules of glucose?

8.24 mol glucose

8.24 x 10^23 mol glucose

8.24 x 10^22 mol glucose

8.24 x 10^21 mol glucose

Answer explanation

To find the number of moles, divide the number of molecules by Avogadro's number (6.022 x 10^23). 4.96 x 10^24 / 6.022 x 10^23 = 8.24 mol glucose.

Tags

NGSS.HS-PS1-7

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