
Avogadro's Number and the Mole Review
Authored by Dorvera Owens
Chemistry
10th Grade
NGSS covered
Used 12+ times

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13 questions
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1.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
How much is one mole?
6.02 x 1023
3 x 108
6.67 x 10-11
6.63 x 10-34
Answer explanation
One mole is equal to Avogadro's number, which is approximately 6.02 x 10^23. This is the correct choice for the amount in one mole.
Tags
112.35.c.8.B
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How many particles are there in 0.250 mol of Ag?
1.505 x 10^23 particles Ag
6.02 x 10^23 particles Ag
3.01 x 10^23 particles Ag
1.204 x 10^24 particles Ag
Answer explanation
0.250 mol of Ag contains 1.505 x 10^23 particles of Ag, as 1 mol of Ag contains 6.02 x 10^23 particles.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How many particles are there in 0.00858 mol NaCl?
5.16 x 10^21 particles NaCl
5.15 x 10^21 particles NaCl
5.15 x 10^22 particles NaCl
5.15 x 10^20 particles NaCl
Answer explanation
0.00858 mol NaCl x 6.022 x 10^23 particles/mol = 5.15 x 10^21 particles NaCl
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How many particles are there in 35.4 mol of CO2?
2.13 x 10^23 particles CO2
2.13 x 10^24 particles CO2
2.13 x 10^25 particles CO2
2.13 x 10^22 particles CO2
Answer explanation
To find the number of particles in 35.4 mol of CO2, use Avogadro's number (6.022 x 10^23 particles/mol) and multiply by the given amount: 35.4 mol * 6.022 x 10^23 particles/mol = 2.13 x 10^24 particles CO2.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How many particles are there in 0.425 kmol of N2?
2.56 x 10^23 particles N2
2.56 x 10^24 particles N2
2.56 x 10^25 particles N2
2.56 x 10^26 particles N2
Answer explanation
0.425 kmol of N2 contains 0.425 x 6.022 x 10^23 particles = 2.56 x 10^23 particles N2
Tags
NGSS.HS-PS1-7
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How many moles of Pb are there in 3.25 x 10^20 atoms of Pb?
5.40 x 10^-4 mol Pb
5.40 x 10^-3 mol Pb
5.40 x 10^-5 mol Pb
5.40 x 10^-6 mol Pb
Answer explanation
To find the number of moles, divide the number of atoms by Avogadro's number (6.022 x 10^23). 3.25 x 10^20 / 6.022 x 10^23 = 5.40 x 10^-4 mol Pb.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How many moles of glucose (C6H12O6) are there in 4.96 x 10^24 molecules of glucose?
8.24 mol glucose
8.24 x 10^23 mol glucose
8.24 x 10^22 mol glucose
8.24 x 10^21 mol glucose
Answer explanation
To find the number of moles, divide the number of molecules by Avogadro's number (6.022 x 10^23). 4.96 x 10^24 / 6.022 x 10^23 = 8.24 mol glucose.
Tags
NGSS.HS-PS1-7
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