Understanding Graham's Law of Effusion

Understanding Graham's Law of Effusion

10th - 12th Grade

8 Qs

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Understanding Graham's Law of Effusion

Understanding Graham's Law of Effusion

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Easy

Created by

Lewis Zellner

Used 1+ times

FREE Resource

8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does Graham's Law of Effusion describe?

The inverse relationship between gas volume and temperature

The direct relationship between gas pressure and volume

The inverse relationship between the rate of effusion and the gas's molar mass

The direct relationship between temperature and the rate of effusion

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is effusion in the context of gases?

The condensation of gas molecules on a surface

The expansion of gas in a vacuum

The escape of gas molecules through a small hole

The process of a gas turning into a liquid

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the rate of effusion for helium calculated using Graham's Law?

By comparing it directly to the molar mass of argon

Through the direct relationship with argon's rate of effusion

Using the inverse square root of the molar mass ratio of helium to argon

By multiplying the rate of effusion of argon with helium's molar mass

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the square root term in Graham's Law represent?

The pressure difference between two gases

The ratio of the gases' temperatures

The volume ratio of the two gases

The ratio of the molar masses of two gases

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it easier to solve for the rate of effusion of helium (r2) rather than argon (r1) in the given example?

Because argon's rate of effusion is already known

Because helium's molar mass is easier to calculate

To avoid flipping the fraction in the equation

Helium's rate of effusion is not influenced by temperature

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the square root of the molar mass ratio in Graham's Law?

It indicates the direct proportionality to effusion rate

It determines the exact speed of gas molecules

It shows the inverse relationship between molar mass and effusion rate

It calculates the pressure exerted by the gas

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is required to identify an unknown gas using its rate of effusion?

The gas's reaction with other chemical substances

The exact temperature and pressure of the gas

Its rate of effusion compared to a known gas

The gas's color and physical state

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the molar mass of a gas affect its effusion time?

Gases with higher molar mass take longer to effuse

Lower molar mass gases take longer to effuse

Higher molar mass gases effuse faster

There is no relationship between molar mass and effusion time