
Substution using Trigonometry Integration
Quiz
•
Mathematics
•
11th Grade
•
Practice Problem
•
Easy
Rachna Math
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9 questions
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1.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
What is the trigonometric substitution rule for integrals?
Trigonometric substitution is used for solving differential equations.
Trigonometric substitution is used for derivatives involving square roots of quadratic expressions.
Trigonometric substitution is used for integrals involving square roots of quadratic expressions.
Trigonometric substitution is used for integrals involving linear expressions.
2.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
How do you apply integration by parts in trigonometric substitution?
Differentiate the integrand instead of integrating
Use trigonometric identities to simplify the integrand
Apply the integration by parts formula directly without any substitutions
Express the integrand in terms of trigonometric functions, make appropriate substitutions, and then apply integration by parts formula.
3.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
How can trigonometric identities be used in integration?
Trigonometric identities can be used to simplify integrals involving trigonometric functions, making them easier to solve.
Trigonometric identities can be used to differentiate trigonometric functions, not integrate them.
Trigonometric identities can be used to convert trigonometric functions to exponential functions.
Trigonometric identities can be used to solve differential equations, not integrals.
4.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Explain the process of using trigonometric substitution in definite integrals.
Trigonometric substitution is only applicable to indefinite integrals
The process of using trigonometric substitution in definite integrals involves identifying the appropriate substitution based on the form of the integral, replacing trigonometric functions with a single variable, simplifying the integral using trigonometric identities, solving the integral in terms of the new variable, and finally converting back to the original variable if necessary.
Trigonometric substitution involves using logarithmic functions instead of trigonometric functions
The process of trigonometric substitution does not require simplifying the integral
5.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
What is the formula for integrating sec^2(x) dx using trigonometric substitution?
tan(x) + C
cos(x) + C
sin(x) + C
cot(x) + C
6.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
When do you use inverse trigonometric substitution in integration?
When the integrand contains expressions involving polynomials, rational functions, or trigonometric functions
When the integrand contains expressions involving sqrt(a^2 - x^2), sqrt(x^2 - a^2), or 1/(a^2 + x^2)
When the integrand contains expressions involving ln(x), e^x, or 1/x
When the integrand contains expressions involving sin(x), cos(x), or tan(x)
7.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
How can trigonometric identities simplify integration problems?
Trigonometric identities only work for differentiation, not integration
Trigonometric identities make integration problems more complicated
Trigonometric identities simplify integration problems by transforming complex trigonometric functions into simpler forms that are easier to integrate.
Trigonometric identities have no effect on integration problems
8.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
What is the purpose of using trigonometric substitution in calculus?
To simplify integrals involving square roots of quadratic expressions.
To solve linear equations
To simplify algebraic expressions
To calculate derivatives of trigonometric functions
9.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Give an example of a trigonometric substitution problem and solve it step by step.
The solution to the integral ∫(x^2) / sqrt(4 - x^2) dx is 2tan^(-1)(x/2) - x*sqrt(4 - x^2)/2 + C.
The solution to the integral ∫(x^2) / sqrt(4 - x^2) dx is 2cos^(-1)(x/2) - x*sqrt(4 - x^2)/2 + C.
The solution to the integral ∫(x^2) / sqrt(4 + x^2) dx is 2sin^(-1)(x/2) - x*sqrt(4 - x^2)/2 + C.
The solution to the integral ∫(x^2) / sqrt(4 - x^2) dx is 2sin^(-1)(x/2) - x*sqrt(4 - x^2)/2 + C.
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