
Moles and Mole Conversions

Quiz
•
Chemistry
•
9th - 12th Grade
•
Medium
Anshu Rana
Used 1+ times
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is Avogadro's number?
6.022 x 10^23
9.80665
12.345
3.14159
Answer explanation
Avogadro's number is 6.022 x 10^23, which represents the number of atoms, ions, or molecules in one mole of a substance.
2.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Calculate the molar mass of H2O.
20.00 g/mol
16.04 g/mol
18.02 g/mol
22.99 g/mol
Answer explanation
The molar mass of H2O is calculated by adding the atomic masses of its elements, which are 2(1.01) + 16.00 = 18.02 g/mol. Therefore, the correct answer is 18.02 g/mol.
3.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
How many moles are in 36 grams of water (H2O)?
10 moles
2 moles
0.5 moles
5 moles
Answer explanation
To find the moles in 36 grams of water, divide the given mass by the molar mass of water (18 grams/mole). 36 grams / 18 grams/mole = 2 moles.
4.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
What is the mass of 2 moles of carbon dioxide (CO2)?
88.02 g
72.03 g
26.04 g
44.01 g
Answer explanation
The molar mass of CO2 is 44.01 g/mol. Therefore, the mass of 2 moles of CO2 is 2 * 44.01 g = 88.02 g.
5.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Convert 5 moles of oxygen (O2) to grams.
10 grams
50 grams
160 grams
200 grams
Answer explanation
To convert moles to grams, use the molar mass of oxygen (O2), which is 32 grams/mol. So, 5 moles of O2 is equal to 5 moles * 32 grams/mole = 160 grams.
6.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Determine the number of moles in 100 grams of calcium carbonate (CaCO3).
2.5 moles
0.5 moles
1.5 moles
0.999 moles
Answer explanation
The molar mass of CaCO3 is 100.09 g/mol. Therefore, 100 grams of CaCO3 is equal to 1 mole (100g / 100.09g/mol = 0.999 moles). So, the correct answer is 0.999 moles.
7.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Calculate the empirical formula of a compound that contains 40% carbon, 6.7% hydrogen, and 53.3% oxygen.
C2H3O2
C3H4O3
C4H5O4
CH3O2
Answer explanation
The empirical formula is calculated by converting the percentages to moles and then dividing by the smallest number of moles. The correct empirical formula is C3H4O3.
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