Python Debugging 2

1. What will be the output of the following program ?

2. L = list('123456')

3. L[0] = L[5] = 0

4. L[3] = L[-2]

   print(L)

• [0, ‘2’, ‘3’, ‘4’, ‘5’, 0] 

• [‘6’, ‘2’, ‘3’, ‘5’, ‘5’, ‘6’] 

• [‘0’, ‘2’, ‘3’, ‘5’, ‘5’, ‘0’]

• [0, ‘2’, ‘3’, ‘5’, ‘5’, 0] 

What will be the output of the following program ?

T = 'geeks'

a, b, c, d, e = T

b = c = '*'

T = (a, b, c, d, e)

print(T)

• (‘g’, ‘*’, ‘*’, ‘k’, ‘s’) 

• (‘g’, ‘e’, ‘e’, ‘k’, ‘s’) 

• (‘geeks’, ‘*’, ‘*’) 

What is the value of L at the end of execution of the following program?

L = [2e-04, 'a', False, 87]

T = (6.22, 'boy', True, 554)

for i in range(len(L)):

if L[i]:

L[i] = L[i] + T[i]

else:

T[i] = L[i] + T[i]

break

• [6.222e-04, ‘aboy’, True, 641] 

• [6.2202, ‘aboy’, 1, 641]

• TypeError 

• [6.2202, ‘aboy’, False, 87] 

What will be the output of the following program ?

T = (2e-04, True, False, 8, 1.001, True)

val = 0

for x in T:

val += int(x)

print(val)

• 11

• 12

• 11.001199999999999 

Answer explanation

Integer value of 2e-04(0.0002) is 0, True holds a value 1 and False a 0, integer value of 1.001 is 1. Thus total 0 + 1 + 0 + 8 + 1 + 1 = 11.

What will be the output of the following program ?

L = [3, 1, 2, 4]

T = ('A', 'b', 'c', 'd')

L.sort()

counter = 0

for x in T:

L[counter] += int(x)

counter += 1

break

print(L)

• [66, 97, 99, 101] 

• [66, 68, 70, 72]

• [66, 67, 68, 69]

• ValueError

Answer explanation

After sort(L), L will be = [1, 2, 3, 4]. Counter = 0, L[0] i.e. 1, x = ‘A’, but Type Conversion of char ‘A’ to integer will throw error and the value cannot be stored in L[0], thus a ValueError.

What will be the output of the following program ?

str1 = '{2}, {1} and {0}'.format('a', 'b', 'c')

str2 = '{0}{1}{0}'.format('abra', 'cad')

print(str1, str2)

• c, b and a abracad0 

• a, b and c abracadabra 

• a, b and c abracadcad 

• c, b and a abracadabra

Answer explanation

String function format takes a format string and an arbitrary set of positional and keyword arguments. For str1 ‘a’ has index 2, ‘b’ index 1 and ‘c’ index 0. str2 has only two indices 0 and 1. Index 0 is used twice at 1st and 3rd time.

What will be the output of the following program ?

import string

Line1 = "And Then There Were None"

Line2 = "Famous In Love"

Line3 = "Famous Were The Kol And Klaus"

Line4 = Line1 + Line2 + Line3

print("And" in Line4)

• True 2 

• True 

• False

• False 2 

Answer explanation

The “in” operator returns True if the strings contains the substring (ie, And), else returns False. 

What will be the output of the following program ?

line = "What will have so will"

L = line.split('a')

for i in L:

print(i, end=' ')

• [‘What’, ‘will’, ‘have’, ‘so’, ‘will’] 

• Wh t will h ve so will 

• What will have so will 

• [‘Wh’, ‘t will h’, ‘ve so will’]

Answer explanation

split() will use ‘a’ as the delimiter. It’ll create partition at ‘a’, thus split() return an array L, which is in [‘Wh’, ‘t will h’, ‘ve so will’]. For loop will print the elements of the list.

What will be the output of the following program ?

tuple = (1, 2, 3, 4)

tuple.append( (5, 6, 7) )

print(len(my_tuple))

• 1

• 2

• 5

• Error

Answer explanation

tuple.append( (5, 6, 7) ) AttributeError: 'tuple' object has no attribute 'append'

What will be the output of the following program ?

tuple1 = (1, 2, 4, 3)

tuple2 = (1, 2, 3, 4)

print(tuple1 < tuple2)

• 1. Error

• 1. True

• 1. False

• 1. Unexpected

Answer explanation

In this case elements will be compared one by one. So, when it compares 4 with 3 it will return False.