Chemistry 101: Writing + Balancing Chemical Equations (Practice)

Chemistry 101: Writing + Balancing Chemical Equations (Practice)

University

5 Qs

quiz-placeholder

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Chemistry 101: Writing + Balancing Chemical Equations (Practice)

Chemistry 101: Writing + Balancing Chemical Equations (Practice)

Assessment

Quiz

Chemistry

University

Hard

NGSS
HS-PS1-1

Standards-aligned

Created by

ILee Gamer

Used 4+ times

FREE Resource

5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 20 pts

Write and balance the chemical equation: potassium sulfite and hydrogen fluoride react to produce potassium fluoride and hydrogen sulfite

K2SO3 + 2HF → 2KF + H2SO3


K2SO3 + HF → KF + H2SO3

2K2SO3 + 2HF → 2KF + 2H2SO3

Answer explanation

Media Image

2.

MULTIPLE CHOICE QUESTION

2 mins • 20 pts

Write out and balance the chemical equation: Beryllium Phosphate and Sodium Bromide react to produce Beryllium Bromide and Sodium Phosphate

Be3(PO4)2 + 6NaBr → 3BeBr + 2Na3PO4

Be2(PO4)3 + 3NaBr → 3Na3PO4 + 2BeBr3

BePO + NaBr → BeBr + NaPO

Be3(PO4) + NaBr → BeBr + Na3PO4

Answer explanation

Media Image

Tags

NGSS.HS-PS1-1

3.

MULTIPLE CHOICE QUESTION

2 mins • 20 pts

Write and balance the chemical equation: Lithium Iodide reacts with Radium Phosphide to produce Lithium Phosphide and Radium Iodide

LiI + Ra3P2 → Li3P + RaI2

6LiI + Ra3P2 → 2Li3P + 3RaI2

LiI + RaP → LiP + RaI

Answer explanation

Media Image

4.

MULTIPLE CHOICE QUESTION

2 mins • 20 pts

Write and balance the chemical equation: Strontium Nitride and Barium Selenide react to produce Strontium Selenide and Barium Nitride

Sr3N2 + BaSe → SrSe + 3BaN

Sr3N2 + 3BaSe → 3SrSe + Ba3N2

SrN + BaSe → SrSe + BaN

8Sr3N2 + 3BaSe → 3SrSe + 7Ba3N2

Answer explanation

Media Image

Tags

NGSS.HS-PS1-1

5.

MULTIPLE CHOICE QUESTION

2 mins • 20 pts

Write out and balance the equation: Francium Fluoride and Rubidium Bromide react to produce Francium Bromide and Rubidium Fluoride

FrF + RbBr → FrBr + RbF

2FrF + 1RbBr → 7FrBr + 3RbF

7Fr2F + 7Rb2Br → 5FrBr + Rb9F

2FrF + 7RbBr → 9FrBr + 3RbF

Answer explanation

Since each cation had a +1 charge, and each anion had a -1 charge, the equation was automatically balanced