test grade 5

0.067 x 1,000 = ...............

• 6.7

• 67

• 0.067

• 670

85.3 x 0.01 = .............

• 853

• 8.53

• 0.853

• 85.03

100 x 0.044=

• 0.44

• 44

• 440

• 4.4

in the division equation 4,234 ÷35=121 , the divisor is .............

• 4,234

• 35

• 121

• 1

if 3,012 ÷ 12 = 251 , then 251 x 12 = ..............

• 3,013

• 3,012

• 3,014

• 3,015

the remainder in the equation 36 ÷ 9 = 4 is ...........

• 36

• 9

• 4

• 0

by using the following area model to divide, the suitable division equation is ................

• 1,456 ÷ 13 = 1,102

• 1,456 ÷ 13 = 211

• 1,456 ÷ 13 = 112

3,123 ÷ 3,123 = .......

• 0

• 3,123

• 1

• 241

0.1 x 0.1 = ..............

• 0.02

• 0.2

• 1

• 0.01

since 35 x 47 = 1,645

,then 3.5 x 4.7 = ..............

• 164.5

• 16.45

• 1645

• 1.645