CBSE - Chemical Kinetics

CBSE - Chemical Kinetics

12th Grade

10 Qs

quiz-placeholder

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CBSE - Chemical Kinetics

CBSE - Chemical Kinetics

Assessment

Quiz

Chemistry

12th Grade

Medium

Created by

Prathiba P

Used 6+ times

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Hydrolysis of an ester follows __________

Zero Order Kinetics

Pseudo First Order Kinetics

First Order Kinetics

Half-life First order Kinetics

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which among the following is a false statement?

Rate of zero order reaction is independent of initial concentration of reactant.

Half life of a third order reaction is inversely proportional to square of initial concentration of the reactant.

Molecularity of a reaction may be zero or fraction.

For a first order reaction, t1/2 = 0.693/K

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following statements about the catalyst is true?

A catalyst accelerates the rate of reaction by bringing down the activation energy

A catalyst makes the reaction feasible by making ∆G more negative.

A catalyst makes equilibrium constant more favourable for forward reaction

A catalyst does not participate in reaction mechanism.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For a chemical reaction A→B, it is found that the rate of reaction doubles when the concentration of A is increased four times. The order of reaction is

Two

One

Half

Zero

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The half life of the first order reaction having rate constant K = 1.7 x 10-5s-1 is

12.1 h

9.7 h

11.3 h

1.8 h

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

In the formation of S02 by contact process;
2SO2 + O2 → 2SO3, the rate of reaction was measured as −d[O2]/dt = 2.5 × 10-4 mol L-1s-1.
The rate of formation of of Sulfur trioxide will be

-5.0 × 10-4 mol L-1s-1

-1.25 × 10-4 mol L-1s-1

3.75 × 10-4 mol L-1s-1

5.00 × 10-4 mol L-1s-1

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

For the reaction N2 + 3H2 → 2NH3 if Δ[NH3]/Δt = 2 × 10-4 mol L-1s-1, the value of −Δ[H2]/Δt would be:

1 × 10-4 mol L-1s-1

3 × 10-4 mol L-1s-1

4 × 10-4 mol L-1s-1

6 × 10-4 mol L-1s-1

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