Quiz about JUMLAH DAN SELISIH DUA SUDUT

Question 1

sin 4x. sin 3x - cos 4x. cos 3x = .....

Accepted Answer

Answer

sin x

Answer

cos x

Answer

Answer

Question 2

Nilai dari $$\sin\ 76^0.\cos\ 16^0-\cos\ 76^0.\sin\ 16^0=\ ....$$

Accepted Answer

$$\frac{1}{2}\sqrt[]{3}$$

Answer

-1

Answer

- $$\frac{1}{2}$$

Answer

0

Answer

$$\frac{1}{2}$$

Question 3

Nilai dari $$\cos\ 70^0.\cos65^0-\sin70^0.\sin65^0=\ ....$$

Accepted Answer

$$-\frac{1}{2}\sqrt[]{2}$$

Answer

$$-\frac{1}{2}$$

Answer

$$\frac{1}{2}$$

Answer

$$\frac{1}{2}\sqrt[]{2}$$

Answer

$$\frac{1}{2}\sqrt[]{3}$$

Question 4

$$Nilai\ dari\frac{ an345^0- an\ 15^0}{1+ an345^0. an15^0}=....$$

Accepted Answer

Answer

Answer

Answer

$$\sqrt[]{3}$$

Answer

$$\frac{1}{3}\sqrt[]{3}$$

Question 5

$$\frac{1}{2}\sqrt[]{3}\sin x+\frac{1}{2}\cos x$$ sama dengan ....

Accepted Answer

$$\cos\left(x-60^0\right)$$

Answer

$$\cos\left(x+60^0\right)$$

Answer

$$\sin\left(x+60^0\right)$$

Answer

$$\sin\left(x-60^0\right)$$

Answer

$$\cos\left(x-30^0\right)$$

Question 6

Nilai dari $$\sin\ 255^0=\ ....$$

Accepted Answer

$$-\frac{1}{4}\left(\sqrt[]{6}+\sqrt[]{2}\right)$$

Answer

$$\frac{1}{4}\left(6-\sqrt[]{2}\right)$$

Answer

$$\frac{1}{4}\left(\sqrt[]{2}-\sqrt[]{6}\right)$$

Answer

$$\frac{1}{4}\left(\sqrt[]{6}-\sqrt[]{2}\right)$$

Answer

$$-\frac{1}{4}\left(\sqrt[]{6}-\sqrt[]{2}\right)$$

Question 7

Nilai dari $$ an\ 165^0=\ .....$$

Accepted Answer

$$-2+\sqrt[]{3}$$

Answer

$$1-\sqrt[]{3}$$

Answer

$$-1+\sqrt[]{3}$$

Answer

$$2-\sqrt[]{3}$$

Answer

$$2+\sqrt[]{3}$$

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