
FISIKA (Essay)
Quiz
•
Physics
•
10th Grade
•
Practice Problem
•
Hard
Sabariah Sabariah
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10 questions
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1.
OPEN ENDED QUESTION
3 mins • 1 pt
Jelaskan apa yang di maksud dengan Suhu dan Kalor
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Answer explanation
Suhu adalah ukuran derajat panas dinginnya suatu benda
Kalor adalah salah satu betuk energi yang dapat berpindah dari benda yang satu ke benda yang lain
2.
OPEN ENDED QUESTION
3 mins • 1 pt
Sebanyak 300 gram air di panaskan dari 300 C menjadi 500 C. Jika kalor jenis air 1 kal /gr0C, Tentukan :
a. Banyaknya kalor dalam satuan kalori !
b. Banyaknya kalor dalam satuan joule !
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Answer explanation
a. Banyaknya kalor dalam satuan kalori ;
Diket : m = 300 gram
c = 1 kal /gr0 K
T1 = 300C = 300 +2730 =3030K
T2 = 500C = 500 +2730=3230K
Δt =3230- 3030
Ditanyakan = a. Q , b. Q
Jawab : a. banyaknya kalor dalam kalori Q = m.c.Δt
Q =(300 )(1)(20) = 6000 kalori
b. banyaknya kalor dalam joule
Q = 4,2 m.c.Δt
Q = (4,2) (300)(t)(20)
Q = 25.200 joule
3.
OPEN ENDED QUESTION
3 mins • 1 pt
Benda bersuhu 200C, mempunyai kapasitas kalor 840 joule/0C.Berapa suhu benda saat kalori sebesar 29.400 joule di berikan pada benda itu ?
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Answer explanation
Diketahui : C = 840 J/0C
Q = 29.400 joule
t1 = 200C
Ditanya = t2....?
Penyelesaian = Perubahan suhu benda
C = Q/Δt
Δt = Q/C
Δt = 29.400/840 = 350c
suhu akhir benda tersebut adalah
t2 = t1 +Δt = 20+ 35 = 550C
4.
OPEN ENDED QUESTION
3 mins • 1 pt
Suhu benda dalam skala Celsius menunjukkan 450 C. Berapa angka yang di tunjukkan dalam skala : Reamur, Fahrenheit, Kelvin !
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Answer explanation
Diketahui : t0c = 450c
Ditanyakan = a. t0R, t0R, t0K
Penyelesaian = a. Temperatur derajat Reamur
t0R = 4/5 . t0c
t0R = 4/5. 450
t0R = 360 R
b. Temperatur derajat Fahrenhait
t0F = (9/5 . t0c) + 32
t0F = (9/5. 450) +32
t0F = 1130 F
c.Temperatur derajat Kelvin :
t0k = t0c +273
t0k = 318 0K
5.
OPEN ENDED QUESTION
3 mins • 1 pt
Temperatur suatu zat 500 R. Hitunglah temperatur tersebut dalam derajat Celcius, Fahrenheit, dan kelvin!
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Answer explanation
Diketahui : t0R = 50 0R
Ditanyakan : a. t0C,t0F,tK0
Penyelesaiaan :
a. Temperatur derajat Celcius
t0c = 5/4 . t0R
t0c = 5/4 . 500
t0C = 62,5 0 C
b. Temperatur derajat Fahrenheit
t0F = (9/4 . t0R) + 32
t0F = (9/4.500) + 32
t0F = 144,50F
c. Temperatur derajat kelvin
t0k = t0k + 273
t0k = 62,5+273 =335,5 0K
6.
OPEN ENDED QUESTION
3 mins • 1 pt
Termometer Fahrenheit yang di letakkan di ruangan br AC menunjukkan 770F. Tentukan angka yang di tunjukkan termometer,Celcius, Reamur, dan Kelvin!
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Answer explanation
Diketahui : t0F = 77 0F
Di tanyakan : a. t0F , t0R , t0K ?
a. Temperatur derajat Celcius
t0c = 5/9 (t0F- 32)
tc = 250c
b. Temperatur derajat Reamur :
t0R = 4/9 . (t0F-32)
t0R =4/9. (770-32 )
t0R = 200 R
c.Temperatur derajat Kelvin
t0k = t0c + 273
t0 k = 2980 K
7.
OPEN ENDED QUESTION
3 mins • 1 pt
Jelaskan tiga cara perpindahan kalor ?
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Answer explanation
Terdapat tiga cara utama perpindahan kalor, yaitu konduksi,konveksi, dan radiasi
1. Konduksi adalah perpindahan kalor melalui kontak langsung antara benda -benda yang berbeda suhu.
2. Konveksi adalah perpindahan kalor melalui pergerakan fluida seperti gas atau cairan.iini terjadi karena ketika suatu bagian fluida di panskan
3.Radiasi adalah perpindahan kalor melalui gelombang elektromagnetik,ketika benda memancarkan radiasi,energi panas di konversimenjadi gelombang elektromagnetik yang dapat merambat melalui ruang hampa.
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