AP stats unit 6 a

Quiz
•
Mathematics
•
12th Grade
•
Medium
Glizia Vieira
Used 11+ times
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11 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The manager of a city recreation center wants to estimate the percent of city residents who favor a proposal to build a new dog park. To gather data, the manager will select a random sample of city residents.
Which of the following is the most appropriate interval for the manager to use for such an estimate?
A one-sample z�-interval for a sample proportion
A one-sample z�-interval for a population proportion
A one-sample z�-interval for a difference between population proportions
A two-sample z�-interval for a difference between population proportions
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Biologists studying horseshoe crabs want to estimate the percent of crabs in a certain area that are longer than 35 centimeters. The biologists will select a random sample of crabs to measure.
Which of the following is the most appropriate method to use for such an estimate?
A one-sample z�-interval for a population proportion
A one-sample z�-interval for a sample proportion
A two-sample z�-interval for a population proportion
A two-sample z�-interval for a difference between population proportions
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A random sample of 500 adults living in a large county was selected and 304 adults from the sample indicated that the unemployment rate was of great concern. What is the standard error of the sample proportion p^?
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A town council wants to estimate the proportion of residents who are in favor of a proposal to upgrade the computers in the town library. A random sample of 100 residents was selected, and 97 of those selected indicated that they were in favor of the proposal. Is it appropriate to assume that the sampling distribution of the sample proportion is approximately normal?
No, because the sample is not large enough to satisfy the normality conditions.
No, because the size of the population is not known.
Yes, because the sample was selected at random.
Yes, because sampling distributions of proportions are modeled with a normal model
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A marketing representative wants to estimate the proportion of people in a state who like the new design on the packaging of a certain cleaning product. The representative interviewed 100 people at a certain supermarket, and 82 people indicated that they liked the new design. Have the conditions for creating a confidence interval for the population proportion been met?
Yes, because the sample was selected at random.
Yes, because sampling distributions of population proportions are modeled with a normal model
Yes, because the sample is large enough to satisfy the normality conditions
No, because the sample may not be representative of all people in the state.
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Sue and Javier are working on a statistics project to estimate the proportion of students at their school who have a pet dog. Sue selects a random sample of 81 students from the 2,400 students at their school, and Javier selects a separate random sample of 64 students. They will both construct a 90 percent confidence interval from their estimates. Consider the situation in which the sample proportion from Sue’s sample is equal to the sample proportion from Javier’s sample. Which of the following statements correctly describes their intervals?
Javier’s interval will have a greater degree of confidence than Sue’s interval will.
The width of Sue’s interval will be wider than the width of Javier’s interval.
The width of Sue’s interval will be the same as the width of Javier’s interval.
The width of Sue’s interval will be narrower than the width of Javier’s interval
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Suppose a 90 percent confidence interval to estimate a population proportion was calculated from a sample proportion of 18 percent and a margin of error of 4 percent. What is the width of the confidence interval?
2 percent
4 percent
8 percent
16 percent
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