Polynomial Review

(2x³ - 5x² + 3x + 7) ÷ (x - 2)

• 2x³ - x² + x + 9
• 2x² - x + 1
• 2x² - x + 1 + 9/x-2
• 2x² - 9x - 15 - 23/x-2

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

(2x³ + 5x² + 9) ÷ (x + 3)

• 2x² - x + 3
• 2x³ - x² + 3x
• 2x² + 11x + 33 + 108/x+3
• 2x² - 5x + 12

Tags

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

            Is (x-2) a factor of             f(x)= x³-8x²+14x-4?

• Yes, (x-2) is a factor. There is a remainder.
• No, (x-2) is  not a factor. The remainder is zero.
• Yes, (x-2) is a factor. The remainder is zero.
• No, (x-2) is  not a factor. There is a remainder. 

Tags

CCSS.HSA.APR.B.2

If you were dividing x⁶ + 4x³ + 2, how many 0's would you need when setting up the top row of your synthetic division?

• 0
• 2
• 4
• 6

Tags

CCSS.HSA.APR.D.6

• Yas

• No

Tags

CCSS.HSA.APR.B.2

Geoff divided (x⁴ + 3x² - 4x - 2) by factor of (x-2) using synthetic division. His work is shown above. Which best describes his mistake?

• Geoff wrote the remainder incorrectly.

• Geoff did not use a zero place holder for the x³ term.

• Geoff added instead of subtracting the rows.

• Geoff should have used -2 as his division since the factor was x-2.

• none of these explanations fit

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.D.6

How many roots would the pictured equation have?

Tags

CCSS.HSA.APR.B.3

Given: f(x) = x³ + 4x² + 25x + 100

Find all the roots

Tags

CCSS.HSA.APR.B.3

CCSS.HSN.CN.A.1

CCSS.HSN.CN.A.2

CCSS.HSN.CN.C.8

• This graph has two imaginary roots because it is a polynomial of degree two.
• This graph has two imaginary roots because it has one hump.
• This graph has two imaginary roots because it touches the x-axis at two points.
• This graph is imaginary because it the graph has shifted up.

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

CCSS.HSA.REI.D.10

All imaginary roots comes in pairs.

• True
• False

Tags

CCSS.HSN.CN.C.7

CCSS.HSN.CN.C.8

CCSS.HSN.CN.C.9