
APP2 PV Diagrams
Authored by Laura Preiser
Physics
11th Grade
NGSS covered
Used 3+ times

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21 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
For the process X→Y, ΔU is greater than zero and
Q<0 and W = 0
Q<0 and W>0
Q>0 and W<0
Q>0 and W=0
Q>0 and W>0
Answer explanation
Process X- Y is isobaric. Constant pressure. The gas is also expanding (increasing volume). When the gas is expanding, the work done is negative. Heat is being added to the system to change the systems volume.
Tags
NGSS.HS-PS3-4
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
For the process Y→Z, Q is greater than zero and
W<0 and ΔU=0
W=0 and ΔU<0
W=0 and ΔU>0
W >0 and ΔU=0
W>0 and ΔU>0
Answer explanation
Process Y-Z is isochoric. This means the volume remains constant. The pressure is increasing. There will be no work done because there is no change in volume. There will be an increase in temperature (PV=nRT). Temperature and internal energy have a direct relationship.
Tags
NGSS.HS-PS3-4
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
An ideal gas undergoes a cyclic process as shown on the graph above of pressure P versus volume V.
During which process is no work done on or by the gas?
AB
BC
CD
DE
EA
Answer explanation
Work done is equivalent the area under the curve. Work done for process AB is zero since there is no area under the curve (and volume is constant).When volume is constant, no work is done.
Tags
NGSS.HS-PS3-1
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
An ideal gas undergoes a cyclic process as shown on the graph above of pressure P versus volume V.
At which point is the gas at its highest temperature?
A
B
C
D
E
Answer explanation
At each point, you are given a triple of information. Pressure, volume and temperature. While temperature is not read off the graph, you can solve for temperature by using the ideal gas law (PV=nRT).
Tags
NGSS.HS-PS3-4
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A certain quantity of an ideal gas initially at temperature T0, pressure p0, and volume V0 is compressed to one-half its initial volume. As shown above, the process may be adiabatic (process 1), isothermal (process 2), or isobaric (process 3).
Which of the following is true of the mechanical work done on the gas?
It is greatest for process 1.
It is greatest for process 3.
It is the same for processes 1 and 2 and less for process 3.
It is the same for processes 2 and 3 and less for process 1.
It is the same for all three processes.
Answer explanation
Work is equivalent to the area under the curve. The greater the area, the greater the work done.
Tags
NGSS.HS-PS2-1
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A certain quantity of an ideal gas initially at temperature T0, pressure p0, and volume V0 is compressed to one-half its initial volume. As shown above, the process may be adiabatic (process 1), isothermal (process 2), or isobaric (process 3).
Which of the following is true of the final temperature of this gas?
It is greatest for process 1.
It is greatest for process 2.
It is greatest for process 3.
It is the same for processes 1 and 2.
It is the same for processes 1 and 3.
Answer explanation
Process 2 is isothermal. The temperature remains the same. Process 3 does have a change in temperature but at a lower pressure. Using the ideal gas law (PV=nRT), you can see the relationship between the three quantities.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A gas is taken from state i to state f along the two-step process shown in the PV diagram above.
How much work is done on the gas during the process described?
0 J
2,000 J
4,000 J
8,000 J
16,000 J
Answer explanation
Calculate area under the curve or use the work equation (W = P Vf-Vi)
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