To find the common RATIO for a sequence that involves "repeated multiplication," such as 100, 80, 64, 51.2, ...

Ratio = $$\frac{2^{nd}Term}{1^{st}Term}$$

Ratio = $$\frac{1^{st}Term}{2^{nd}Term}$$

Ratio = $$2^{nd}Term-1^{st}Term$$

Ratio = $$1^{st}Term-2^{nd}Term$$

To find the common DIFFERENCE for a sequence that involves "repeated addition," such as -8, -2, 4, 10, ...

Difference = $$2^{nd}Term-1^{st}Term$$

Difference = $$\frac{1^{st}Term}{2^{nd}Term}$$

Difference = $$\frac{2^{nd}Term}{1^{st}Term}$$

Difference = $$1^{st}Term-2^{nd}Term$$

Chapter 7 Summative #2 PREVIEW

9th - 12th Grade

•

45 Qs

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Chapter 7 Summative #2 PREVIEW

Quiz

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Medium

•

CCSS

HSF.BF.A.2, HSF.LE.A.2, HSF-LE.A.1A

Standards-aligned

Rebecca Stuckey

Used 14+ times

FREE Resource

45 questions

Show all answers

MATCH QUESTION

1 min • 1 pt

Match each graph to its description.

Linear Increase

Exponential Growth

Exponential Decay

Linear Decrease

Tags

CCSS.HSF-IF.C.7E

MATCH QUESTION

1 min • 1 pt

Match each formula to its description.

Linear Decrease

Linear Increase

Exponential Decay

Exponential Growth

Tags

CCSS.HSF.LE.A.2

MATCH QUESTION

1 min • 1 pt

Match each formula with its description.

Exponential Decay

Linear Decrease

Exponential Growth

Linear Increase

Tags

CCSS.HSF-LE.A.1A

MATCH QUESTION

1 min • 1 pt

Match each equation below to its description.

Linear Decrease

Exponential Growth

Linear Increase

Exponential Decay

Tags

CCSS.HSF.LE.A.2

MATCH QUESTION

1 min • 1 pt

Match each equation below to its description.

Exponential Decay

Linear Increase

Linear Decrease

Exponential Growth

Answer explanation

f(x) = 5x - 1/2
This function results in LINEAR INCREASE
* mx + b, with x^1
* slope is (+) since m = 5

Tags

CCSS.HSF.LE.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Answer explanation

3, 15, 75, 375, ...
ratio = 15/3 = 5
Start with 3, multiply by 5 "n-1" times to get to the "Nth Term"
Nth = 1st * ratio ^ (n-1)
f(n) = 3 * 5 ^ (n-1)

Tags

CCSS.HSF.BF.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Answer explanation

9375, 1875, 375, 75, ...
ratio = 9375/1875 = 1/5
Start with 9375, multiply by 1/5 "n-1" times to get to the "Nth Term"
Nth = 1st * ratio ^ (n-1)
f(n) = 9375 * (1/5) ^ (n-1)

Tags

CCSS.HSF.BF.A.2

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Chapter 7 Summative #2 PREVIEW

45 questions

Match each graph to its description.

Match each formula to its description.

Match each formula with its description.

Match each equation below to its description.

Match each equation below to its description.

f(x) = 5x - 1/2
This function results in LINEAR INCREASE
* mx + b, with x^1
* slope is (+) since m = 5

3, 15, 75, 375, ...
ratio = 15/3 = 5
Start with 3, multiply by 5 "n-1" times to get to the "Nth Term"
Nth = 1st * ratio ^ (n-1)
f(n) = 3 * 5 ^ (n-1)

9375, 1875, 375, 75, ...
ratio = 9375/1875 = 1/5
Start with 9375, multiply by 1/5 "n-1" times to get to the "Nth Term"
Nth = 1st * ratio ^ (n-1)
f(n) = 9375 * (1/5) ^ (n-1)

3, 15, 27, 39, ...
difference = 15 - 3 = 12
Start with 3, add 12 "n-1" times to get to the "Nth Term"
Nth = 1st + difference*(n-1)
f(n) = 3 + 12(n-1)

15, 3, -9, -21, ...
difference = 3 - 15 = -12
Start with 3, subtract 12 "n-1" times to get to the "Nth Term"
Nth = 1st - difference*(n-1)
f(n) = 3 - 12(n-1)

The EXPLICIT FORMULA for a sequence of terms where the pattern of change involves REPEATED MULTIPLICATION is --

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Chapter 7 Summative #2 PREVIEW

45 questions

Match each graph to its description.

Match each formula to its description.

Match each formula with its description.

Match each equation below to its description.

Match each equation below to its description.

f(x) = 5x - 1/2This function results in LINEAR INCREASE* mx + b, with x^1* slope is (+) since m = 5

3, 15, 75, 375, ...ratio = 15/3 = 5Start with 3, multiply by 5 "n-1" times to get to the "Nth Term"Nth = 1st * ratio ^ (n-1)f(n) = 3 * 5 ^ (n-1)

9375, 1875, 375, 75, ...ratio = 9375/1875 = 1/5Start with 9375, multiply by 1/5 "n-1" times to get to the "Nth Term"Nth = 1st * ratio ^ (n-1)f(n) = 9375 * (1/5) ^ (n-1)

3, 15, 27, 39, ...difference = 15 - 3 = 12Start with 3, add 12 "n-1" times to get to the "Nth Term"Nth = 1st + difference*(n-1)f(n) = 3 + 12(n-1)

15, 3, -9, -21, ...difference = 3 - 15 = -12Start with 3, subtract 12 "n-1" times to get to the "Nth Term"Nth = 1st - difference*(n-1)f(n) = 3 - 12(n-1)

The EXPLICIT FORMULA for a sequence of terms where the pattern of change involves REPEATED MULTIPLICATION is --

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f(x) = 5x - 1/2
This function results in LINEAR INCREASE
* mx + b, with x^1
* slope is (+) since m = 5

3, 15, 75, 375, ...
ratio = 15/3 = 5
Start with 3, multiply by 5 "n-1" times to get to the "Nth Term"
Nth = 1st * ratio ^ (n-1)
f(n) = 3 * 5 ^ (n-1)

9375, 1875, 375, 75, ...
ratio = 9375/1875 = 1/5
Start with 9375, multiply by 1/5 "n-1" times to get to the "Nth Term"
Nth = 1st * ratio ^ (n-1)
f(n) = 9375 * (1/5) ^ (n-1)

3, 15, 27, 39, ...
difference = 15 - 3 = 12
Start with 3, add 12 "n-1" times to get to the "Nth Term"
Nth = 1st + difference*(n-1)
f(n) = 3 + 12(n-1)

15, 3, -9, -21, ...
difference = 3 - 15 = -12
Start with 3, subtract 12 "n-1" times to get to the "Nth Term"
Nth = 1st - difference*(n-1)
f(n) = 3 - 12(n-1)