sin 60 ° 60\degree 6 0 ° cos 30 ° 30\degree 3 0 ° - cos 60 ° 60\degree 6 0 ° sin 30 ° 30\degree 3 0 ° =...

1 2 3 \frac{1}{2}\sqrt{3} 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 2 \frac{1}{2}\sqrt{2} 2 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Sebuah tangga yang panjangnya 2 m disandarkan ke bagian paling atas sebuah tembok. Jika tinggi tembok = 3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> m dan α \alpha α merupakan sudut yang dibentuk oleh tangga dan tembok, maka α \alpha α =...

5 12 π \frac{5}{12}\pi 1 2 5 π

Jika sin A = 1 2 3 \ \frac{1}{2}\sqrt{3} 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> dan A lancip, maka tan A = ...

3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 3 3 \frac{1}{3}\sqrt{3} 3 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 3 \frac{1}{2}\sqrt{3} 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

sin 1 2 π \frac{1}{2}\pi 2 1 π . sin 1 3 π \frac{1}{3}\pi 3 1 π . sin 1 6 π \frac{1}{6}\pi 6 1 π =...

1 4 3 \frac{1}{4}\sqrt{3} 4 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 3 \frac{1}{2}\sqrt{3} 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 2 \frac{1}{2}\sqrt{2} 2 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 4 2 \frac{1}{4}\sqrt{2} 4 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Penyelesaian dari persamaan $$2\sin^2x-\sin x-1=0$$ untuk $$180\degree\le x\le360\degree$$ adalah ...

$$210\degree$$ dan $$330\degree$$

$$150\degree$$ dan $$180\degree$$

$$180\degree$$ dan $$210\degree$$

$$240\degree$$ dan $$270\degree$$

$$300\degree$$ dan $$330\degree$$

Himpunan penyelesaian dari tan ⁡ ⁡ ( x + 25 ° ) = tan ⁡ ⁡ 50 ° \tan⁡(x+25°)=\tan⁡50° tan ⁡ ( x + 2 5 ° ) = tan ⁡ 5 0 ° untuk 0 ° ≤ x ≤ 360 ° 0°≤x≤360° 0 ° ≤ x ≤ 3 6 0 ° adalah . . .

{ 25 ° , 205 ° } \left\{25°,205°\right\} { 2 5 ° , 2 0 5 ° }

{ 25 ° , 105 ° } \left\{25°,105°\right\} { 2 5 ° , 1 0 5 ° }

{ 25 ° , 305 ° } \left\{25°,305°\right\} { 2 5 ° , 3 0 5 ° }

{ 75 ° , 105 ° } \left\{75°,105°\right\} { 7 5 ° , 1 0 5 ° }

{ 75 ° , 205 ° } \left\{75°,205°\right\} { 7 5 ° , 2 0 5 ° }

diketahui cos 2x = cos 6 0 o 60^o 6 0 o , tentukan nilai x yang memenuhi untuk 0 o ≤ x ≤ 18 0 o 0^o\le x\le180^o 0 o ≤ x ≤ 1 8 0 o

3 0 o d a n 15 0 o 30^odan\ 150^o 3 0 o d a n 1 5 0 o

1 5 o d a n 3 0 o 15^odan\ 30^o 1 5 o d a n 3 0 o

6 0 o d a n 12 0 o 60^odan\ 120^o 6 0 o d a n 1 2 0 o

9 0 o d a n 18 0 o 90^o\ dan\ 180^o 9 0 o d a n 1 8 0 o

18 0 o d a n 36 0 o 180^odan\ 360^o 1 8 0 o d a n 3 6 0 o

Nilai dari Sin 60 adalah ...

1 2 3 \frac{1}{2}\sqrt{3} 2 1 3 <path d="M 95 702 c -2.7 0 -7.17 -2.7 -13.5 -8 c -5.8 -5.3 -9.5 -10 -9.5 -14 c 0 -2 0.3 -3.3 1 -4 c 1.3 -2.7 23.83 -20.7 67.5 -54 c 44.2 -33.3 65.8 -50.3 66.5 -51 c 1.3 -1.3 3 -2 5 -2 c 4.7 0 8.7 3.3 12 10 s 173 378 173 378 c 0.7 0 35.3 -71 104 -213 c 68.7 -142 137.5 -285 206.5 -429 c 69 -144 104.5 -217.7 106.5 -221 c 5.3 -9.3 12 -14 20 -14 H 400000 v 40 H 845.272 s -225.272 467 -225.272 467 s -235 486 -235 486 c -2.7 4.7 -9 7 -19 7 c -6 0 -10 -1 -12 -3 s -194 -422 -194 -422 s -65 47 -65 47 Z M 834 80 H 400000 v 40 H 845 Z" />

1 3 3 \frac{1}{3}\sqrt{3} 3 1 3 <path d="M 95 702 c -2.7 0 -7.17 -2.7 -13.5 -8 c -5.8 -5.3 -9.5 -10 -9.5 -14 c 0 -2 0.3 -3.3 1 -4 c 1.3 -2.7 23.83 -20.7 67.5 -54 c 44.2 -33.3 65.8 -50.3 66.5 -51 c 1.3 -1.3 3 -2 5 -2 c 4.7 0 8.7 3.3 12 10 s 173 378 173 378 c 0.7 0 35.3 -71 104 -213 c 68.7 -142 137.5 -285 206.5 -429 c 69 -144 104.5 -217.7 106.5 -221 c 5.3 -9.3 12 -14 20 -14 H 400000 v 40 H 845.272 s -225.272 467 -225.272 467 s -235 486 -235 486 c -2.7 4.7 -9 7 -19 7 c -6 0 -10 -1 -12 -3 s -194 -422 -194 -422 s -65 47 -65 47 Z M 834 80 H 400000 v 40 H 845 Z" />

3 \sqrt{3} 3 <path d="M 95 702 c -2.7 0 -7.17 -2.7 -13.5 -8 c -5.8 -5.3 -9.5 -10 -9.5 -14 c 0 -2 0.3 -3.3 1 -4 c 1.3 -2.7 23.83 -20.7 67.5 -54 c 44.2 -33.3 65.8 -50.3 66.5 -51 c 1.3 -1.3 3 -2 5 -2 c 4.7 0 8.7 3.3 12 10 s 173 378 173 378 c 0.7 0 35.3 -71 104 -213 c 68.7 -142 137.5 -285 206.5 -429 c 69 -144 104.5 -217.7 106.5 -221 c 5.3 -9.3 12 -14 20 -14 H 400000 v 40 H 845.272 s -225.272 467 -225.272 467 s -235 486 -235 486 c -2.7 4.7 -9 7 -19 7 c -6 0 -10 -1 -12 -3 s -194 -422 -194 -422 s -65 47 -65 47 Z M 834 80 H 400000 v 40 H 845 Z" />

1 2 2 \frac{1}{2}\sqrt{2} 2 1 2 <path d="M 95 702 c -2.7 0 -7.17 -2.7 -13.5 -8 c -5.8 -5.3 -9.5 -10 -9.5 -14 c 0 -2 0.3 -3.3 1 -4 c 1.3 -2.7 23.83 -20.7 67.5 -54 c 44.2 -33.3 65.8 -50.3 66.5 -51 c 1.3 -1.3 3 -2 5 -2 c 4.7 0 8.7 3.3 12 10 s 173 378 173 378 c 0.7 0 35.3 -71 104 -213 c 68.7 -142 137.5 -285 206.5 -429 c 69 -144 104.5 -217.7 106.5 -221 c 5.3 -9.3 12 -14 20 -14 H 400000 v 40 H 845.272 s -225.272 467 -225.272 467 s -235 486 -235 486 c -2.7 4.7 -9 7 -19 7 c -6 0 -10 -1 -12 -3 s -194 -422 -194 -422 s -65 47 -65 47 Z M 834 80 H 400000 v 40 H 845 Z" />

1 3 2 \frac{1}{3}\sqrt{2} 3 1 2 <path d="M 95 702 c -2.7 0 -7.17 -2.7 -13.5 -8 c -5.8 -5.3 -9.5 -10 -9.5 -14 c 0 -2 0.3 -3.3 1 -4 c 1.3 -2.7 23.83 -20.7 67.5 -54 c 44.2 -33.3 65.8 -50.3 66.5 -51 c 1.3 -1.3 3 -2 5 -2 c 4.7 0 8.7 3.3 12 10 s 173 378 173 378 c 0.7 0 35.3 -71 104 -213 c 68.7 -142 137.5 -285 206.5 -429 c 69 -144 104.5 -217.7 106.5 -221 c 5.3 -9.3 12 -14 20 -14 H 400000 v 40 H 845.272 s -225.272 467 -225.272 467 s -235 486 -235 486 c -2.7 4.7 -9 7 -19 7 c -6 0 -10 -1 -12 -3 s -194 -422 -194 -422 s -65 47 -65 47 Z M 834 80 H 400000 v 40 H 845 Z" />

Untuk 0 ° ≤ x ≤ 360 ° 0\degree\le x\le360\degree 0 ° ≤ x ≤ 3 6 0 ° dalam persamaan 2 sin ⁡ x − 2 = 0 2\sin x-\sqrt{2}=0 2 sin x − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> = 0 mempunyai himpunan penyelesaian ...

{ 45 ° , 135 ° } \left\{45\degree,135\degree\right\} { 4 5 ° , 1 3 5 ° }

{ 45 ° , 315 ° } \left\{45\degree,315\degree\right\} { 4 5 ° , 3 1 5 ° }

{ 135 ° , 225 ° } \left\{135\degree,225\degree\right\} { 1 3 5 ° , 2 2 5 ° }

{ 45 ° , 135 ° , 225 ° } \left\{45\degree,135\degree,225\degree\right\} { 4 5 ° , 1 3 5 ° , 2 2 5 ° }

{ 45 ° , 135 ° , 225 ° , 315 ° } \left\{45\degree,135\degree,225\degree,315\degree\right\} { 4 5 ° , 1 3 5 ° , 2 2 5 ° , 3 1 5 ° }

Trigonometri

Quiz

•

Mathematics

•

2nd Grade

•

Practice Problem

•

Hard

Nesy Widyastuti

FREE Resource

120 questions

Show all answers

1.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Manakah pernyataan berikut yang salah ....

\cos\alpha=\frac{samping}{miring}

$\tan\alpha=\frac{depan}{samping}$

$\operatorname{cotan}\alpha=\frac{samping}{miring}$

$\sin\alpha=\frac{depan}{miring}$

$\sec\alpha=\frac{miring}{depan}$

2.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Nilai x pada interval $0\degree\le x\le360\degree$ yang memenuhi persamaan tan x = - 1

$0\degree$

$360\degree$

$315\degree$

$270\degree$

$135\degree$

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Perbandingan antara sisi samping dan sisi miring pada segitiga siku-siku dalam trgionometri disebut ....

cosecan

sinus

cosinus

secan

tangen

4.

MULTIPLE CHOICE QUESTION

30 sec • 10 pts

Perbandingan antara sisi samping dan sisi miring pada segitiga siku-siku dalam trigonometri disebut...

Sinus

Cosinus

Tangen

Cotangen

Cosecan

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Keliling suatu segienam beraturan adalah 72 cm. Luas segi enam tersebut adalah ...

432 √3 cm²

432 cm²

216 √3 cm²

216 √2 cm²

216 cm²

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Create a free account and access millions of resources

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever

or continue with

Microsoft

Apple

Others

Already have an account?

Similar Resources on Wayground

120 questions

Kuiz Matematik Tingkatan 2

Quiz

•

KG - University

121 questions

1B H7&9 vermenigvuldigen en delen

Quiz

•

2nd - 6th Grade

Popular Resources on Wayground

10 questions

Honoring the Significance of Veterans Day

Interactive video

•

6th - 10th Grade

9 questions

FOREST Community of Caring

Lesson

•

1st - 5th Grade

10 questions

Exploring Veterans Day: Facts and Celebrations for Kids

Interactive video

•

6th - 10th Grade

19 questions

Veterans Day

Quiz

•

5th Grade

14 questions

General Technology Use Quiz

Quiz

•

8th Grade

25 questions

Multiplication Facts

Quiz

•

5th Grade

15 questions

Circuits, Light Energy, and Forces

Quiz

•

5th Grade

19 questions

Thanksgiving Trivia

Quiz

•

6th Grade

Discover more resources for Mathematics

20 questions

Multiplication Mastery Checkpoint

Quiz

•

1st - 5th Grade

20 questions

Subtraction Facts

Quiz

•

2nd Grade

20 questions

Multiplication Facts

Quiz

•

2nd - 3rd Grade

20 questions

Place Value

Quiz

•

KG - 3rd Grade

20 questions

Counting Money

Quiz

•

2nd Grade

20 questions

Measurement

Quiz

•

2nd Grade

10 questions

2-Digit Addition with Regrouping

Quiz

•

2nd Grade

10 questions

3 Digit Subtraction With and Without Regrouping

Quiz

•

2nd Grade

Trigonometri

120 questions

Manakah pernyataan berikut yang salah ....

Nilai x pada interval $0\degree\le x\le360\degree$ yang memenuhi persamaan tan x = - 1

Perbandingan antara sisi samping dan sisi miring pada segitiga siku-siku dalam trgionometri disebut ....

Perbandingan antara sisi samping dan sisi miring pada segitiga siku-siku dalam trigonometri disebut...

Keliling suatu segienam beraturan adalah 72 cm. Luas segi enam tersebut adalah ...

Pernyataan yang benar berikut ini adalah ....

Pada segitiga lancip ABC diketahui panjang sisi AC = 4cm, AB = 5 cm, dan cos B =4/5 ,
maka cos C = …

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Trigonometri

120 questions

Manakah pernyataan berikut yang salah ....

Nilai x pada interval 0°≤x≤360°0\degree\le x\le360\degree0°≤x≤360° yang memenuhi persamaan tan x = - 1

Perbandingan antara sisi samping dan sisi miring pada segitiga siku-siku dalam trgionometri disebut ....

Perbandingan antara sisi samping dan sisi miring pada segitiga siku-siku dalam trigonometri disebut...

Keliling suatu segienam beraturan adalah 72 cm. Luas segi enam tersebut adalah ...

Pernyataan yang benar berikut ini adalah ....

Pada segitiga lancip ABC diketahui panjang sisi AC = 4cm, AB = 5 cm, dan cos B =4/5 , maka cos C = …

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Nilai x pada interval $0\degree\le x\le360\degree$ yang memenuhi persamaan tan x = - 1

Pada segitiga lancip ABC diketahui panjang sisi AC = 4cm, AB = 5 cm, dan cos B =4/5 ,
maka cos C = …