Chapter 2 Review (Honors Precalculus)

Chapter 2 Review (Honors Precalculus)

10th - 12th Grade

18 Qs

quiz-placeholder

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Chapter 2 Review (Honors Precalculus)

Chapter 2 Review (Honors Precalculus)

Assessment

Quiz

Mathematics

10th - 12th Grade

Medium

CCSS
HSA.APR.B.3, HSA.APR.D.6, HSF.IF.B.6

+9

Standards-aligned

Created by

Megan Omand

Used 12+ times

FREE Resource

18 questions

Show all answers

1.

FILL IN THE BLANK QUESTION

5 mins • 5 pts

Answer explanation

To find the average rate of change of f(x) = 2x^2 + 1 from x = 0 to x = 1, calculate f(1) - f(0) = (2(1)^2 + 1) - (2(0)^2 + 1) = 3 - 1 = 2. Then divide by the interval length: 2 / (1 - 0) = 2. The correct answer is 0.

Tags

CCSS.HSF.IF.B.6

2.

FILL IN THE BLANK QUESTION

5 mins • 5 pts

Media Image

Given the graph, find the average rate of change from x = -1 to x = 2.

Answer explanation

To find the average rate of change from x = -1 to x = 2, calculate the change in y-values divided by the change in x-values. If the graph shows equal y-values at these points, the average rate of change is 0.

Tags

CCSS.HSF.IF.B.6

3.

MULTIPLE CHOICE QUESTION

5 mins • 5 pts

The function h(t) = -8t2 + 24t + 32 models the approximate height of an object t seconds after it is launched. How many seconds does it take the object to hit the ground?

32 seconds

1 seconds

4 seconds

1 second and 4 seconds

-1 second and 4 seconds

Answer explanation

To find when the object hits the ground, set h(t) = 0: -8t^2 + 24t + 32 = 0. Using the quadratic formula, we find t = 4 seconds (the positive solution). Thus, it takes 4 seconds for the object to hit the ground.

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

4.

MULTIPLE CHOICE QUESTION

5 mins • 10 pts

A dolphin jumps from the water at at initial velocity of 16 feet per second. The equation h = -8t2 + 16t models the dolphin's height at any given time, t. What is the maximum height the dolphin jumps?

1 foot

5 feet

7 feet

8 feet

12 feet

Answer explanation

To find the maximum height, use the vertex formula for a parabola. The maximum height occurs at t = -b/(2a) = 16/(2*8) = 1 second. Plugging t = 1 into the height equation gives h = -8(1)^2 + 16(1) = 8 feet.

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.1

5.

MULTIPLE CHOICE QUESTION

5 mins • 10 pts

(x3-2x2+x-6)÷(x+3)

x2-5x+16+(-54/x+3)

x2+x+16+(-54/x+3)

x2+x-2

x2+5x-16+(54/x+3)

Answer explanation

To divide (x^3 - 2x^2 + x - 6) by (x + 3), use polynomial long division. The result is x^2 - 5x + 16 with a remainder of -54. Thus, the answer is x^2 - 5x + 16 + (-54/(x + 3)), matching the correct choice.

Tags

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

CCSS.HSA.SSE.B.3

6.

MULTIPLE CHOICE QUESTION

1 min • 5 pts

Media Image

Which of the following could be the equation of this polynomial function?

Answer explanation

The correct choice, \( f(x) = (x+5)^2(x+1)(x-3) \), indicates a double root at \( x = -5 \) and single roots at \( x = -1 \) and \( x = 3 \). This matches the behavior of the polynomial function.

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

7.

MULTIPLE CHOICE QUESTION

1 min • 5 pts

Media Image

What could be the equation of this polynomial function?

Answer explanation

The correct polynomial function is given by the roots at x=4, x=-1, and x=-3. The choice f(x)=(x-4)(x+1)(x+3) accurately reflects these roots, while the other options include unnecessary multiplicities or incorrect roots.

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

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