Equations of motion

What is the value of final velocity when the body starts from rest.

Acceleration = a

Time taken = t

Initial velocity = u

• u

• a/t

• at

• ut

A body starts from rest and moves with constant acceleration of 6 m/s2

If it travels for 5 seconds.

Find the distance covered?

• 75 m

• 75 cm

• 90 m

• 75 km

A ball falls freely from a tower of height 125m. If acceleration due to gravity is 10 m/s2 find the time taken to reach the ground.

• 25 seconds

• 5 seconds

• 12.5 seconds

• Square root of 125

A ball is thrown vertically up with a velocity 20 m/s. It takes to come back down.

[ g = 10 m/s2 ]

• 2 s

• 5 s

• 10 s

• 4 s

A ball is thrown vertically upwards from the top of building of height 24.5 m with initial velocity 19.6 m/s and then it falls on the ground . Taking acceleration due to gravity as 9.8 m/s2

Find the total time of the journey?

[numerical value<space>seconds]

Find the maximum height reached by the body when thrown vertically upward if it is thrown with the initial velocity = u and the acceleration due to gravity = g.

• u X g

• u/g

• ( u X u) + 2g

• (u X u) / 2g

A body moves from rest with a uniform acceleration and travels 270 m in 3 s. Find the velocity of the body at 10 s after start.

A train travels with a speed of 20 m/s is brought to rest by applying breaks in 5 s. Calculate retardation.

• - 4

• - 4 m/s

• 4 m/s2

• - 4 m/s2

A body starts from rest with a uniform acceleration 'a' for some time and decelerates 'b' to comes to rest.

Find the maximum velocity of the body if the total time elapsed = t.

[If you can't solve this you can skip]

• ab/t

• abt/(a+b)

• ab/(a+b)

• t/(a-b)

• Skip

How was this quiz

• Difficult

• Easy

• Moderate