Point Slope Form

 $y-4=-\frac{1}{2}\left(x+3\right)$  

Graph the line described by each equation.

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 $\left(2,\ 7\right)\ and\ \left(4,\ -4\right)\ are\ on\ the\ line$  Write the equation that describes each line in slope intercept form.

•  $y=-\frac{11}{2}x+18$  

•  $y=-5x-3$  

•  $y=2x-6$  

•  $y=\frac{1}{4}x-1$  

 $\left(-1,\ -4\right)\ and\ \left(6,\ 10\right)$  

Each pair of points is a line. Find the intercepts.

•  $x-int:\ 1;\ y-int:\ -2$  

•  $x-int:\ 6;\ y-int:\ 8$  

•  $x-int:\ -6;\ y-int:\ 9$  

 $y=-x;\ y-3=-1\left(x+9\right);\ y-6=\frac{1}{2}\left(x-14\right);\ y+1=\frac{1}{2}x$  Identify which lines are parallel.

•  $y=-x\ and\ y-3=-1\left(x+9\right)$  

•  $y-6=\frac{1}{2}\left(x-14\right)\ and\ y+1=\frac{1}{2}x$  

•  $y=-x\ and\ y-3=-1\left(x+9\right)\ ;\ y-6=\frac{1}{2}\left(x-14\right)\ and\ y+1=\frac{1}{2}x$  

Show that ABC is a right triangle.

• $\overline{AB}\ is\ perpendicular\ to\ \overline{BC}$

• $\overline{AB}\ is\ perpendicular\ to\ \overline{AC}$

• $\overline{BC}\ is\ perpendicular\ to\ \overline{AC}$

 $y-9=3\left(x+1\right);\ y=-\frac{1}{3}x+5;\ y=0;\ x=6$  Identify which lines are perpendicular

•  $y-9=3\left(x+3\right)\ and\ y=-\frac{1}{3}x+5;\ y=0\ and\ x=6$  

•  $y-9=3\left(x+3\right)\ and\ y=-\frac{1}{3}x+5$  

•  $y=0\ and\ x=6$