Solving Systems of Equations and Inequalities Review

Solve the system of equations by substitution.

x - 7y = -21

2x -14y = -42

• infinite

• no solution

• one solution

Tags

CCSS.8.EE.C.8B

Solve the system of equations by elimination.

x - y = -10

x - 6y = -25

• (3,-7)

• (-7,3)

• (-5,5)

• (5,-5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations by elimination.

2x + 2y = 28

8x - 2y = 22

• (5,9)

• (9,5)

• (1,13)

• (13,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

The sum of two numbers is 30 and their difference is 12. Define the variables.

• x = 1st number

  y = 2nd number

• x = 30

  y = 12

• x = 1st number

  x = 1st number

Tags

CCSS.8.EE.C.8C

The sum of two numbers is 30 and their difference is 12. Write the system of equations.

• x + y = 30

  x - y = 12

• x + y = 12

  x - y = 30

Tags

CCSS.HSA.CED.A.3

Solve the system of equations by substitution.

y = 7x + 6

4x - 3y = 16

• (-2,-8)

• (-8,-2)

• (-2,20)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

The sum of two numbers is 30 and their difference is 12. Find the two numbers.

• 51 and 9

• 21 and 9

• 9 and 9

Tags

CCSS.8.EE.C.8C

The cost of 12 oranges and 7 apples is $5.36. Eight oranges and 5 apples cost $3.68. Define the variables.

• x = number of oranges

  y = number of apples

• x = price of orange

  y = price of apple

Tags

CCSS.8.EE.C.8C

The cost of 12 oranges and 7 apples is $5.36. Eight oranges and 5 apples cost $3.68. Write the system of equations.

• 12x + 7y = 3.68

  8x + 5y = 5.36

• 12x + 8x = 5.36

  7y + 5y = 3.68

• 12x + 7y = 5.36

  8x + 5y = 3.68

Tags

CCSS.HSA.CED.A.3

The cost of 12 oranges and 7 apples is $5.36. Eight oranges and 5 apples cost $3.68. Find the cost of each.

• The cost of one orange is $0.26, and the cost of one apple is $0.32.

• The cost of one orange is $0.32, and the cost of one apple is $0.26.

Tags

CCSS.8.EE.C.8C