PT LƯỢNG GIÁC CƠ BẢN

PT LƯỢNG GIÁC CƠ BẢN

1st - 12th Grade

10 Qs

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PT LƯỢNG GIÁC CƠ BẢN

PT LƯỢNG GIÁC CƠ BẢN

Assessment

Quiz

Mathematics

1st - 12th Grade

Medium

Created by

Thao Lê

Used 1+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Giải phương trình lượng giác sau: 2sinx=3

 x=π2+k2π, x=π3+k2π, kZx=\frac{\pi}{2}+k2\pi,\ x=-\frac{\pi}{3}+k2\pi,\ k\in Z 

x=π4+kπ, x=3π4+kπ, kZx=\frac{\pi}{4}+k\pi,\ x=\frac{3\pi}{4}+k\pi,\ k\in Z

vô nghiệm

 x=π4+k2π, x=π6+k2π,kZx=\frac{\pi}{4}+k2\pi,\ x=-\frac{\pi}{6}+k2\pi,k\in Z 

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Giải phương trình lượng giác sau: sin2x=1

x=π3+k2π, x=π3+k2π, kZx=\frac{\pi}{3}+k2\pi,\ x=-\frac{\pi}{3}+k2\pi,\ k\in Z

 x=π4+kπ, kZx=\frac{\pi}{4}+k\pi,\ k\in Z 

x=π3+kπx=\frac{\pi}{3}+k\pi

x=π6+k2π, x=π6+k2π,kZx=\frac{\pi}{6}+k2\pi,\ x=-\frac{\pi}{6}+k2\pi,k\in Z

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Giải phương trình lượng giác sau:



 sin2x = -1

 x=π4+k2π, x=π6+k2π, kZx=\frac{\pi}{4}+k2\pi,\ x=-\frac{\pi}{6}+k2\pi,\ k\in Z 

 x=π4+kπ, kZx=-\frac{\pi}{4}+k\pi,\ k\in Z 

 x=π4+kπx=\frac{\pi}{4}+k\pi 

x=π6+k2π, x=π6+k2π,kZx=\frac{\pi}{6}+k2\pi,\ x=-\frac{\pi}{6}+k2\pi,k\in Z

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Phương trình

 sin(2xπ3)=13 \sin\left(2x-\frac{\pi}{3}\right)=\frac{1}{3\ }  có nghiệm là

 x=π3+13+k2π(kZ) vaˋ  x=π3+π13+k2π(kZ)x=\frac{\pi}{3}+\frac{1}{3}+k2\pi\left(k\in Z\right)\ và\ \ x=\frac{\pi}{3}+\pi-\frac{1}{3}+k2\pi\left(k\in Z\right)  

 x=π6+12arcsin 13+kπ(kZ)x=\frac{\pi}{6}+\frac{1}{2}\arcsin\ \frac{1}{3}+k\pi\left(k\in Z\right)  và 
 x=2π312arcsin 13+kπ(kZ)x=\frac{2\pi}{3}-\frac{1}{2}\arcsin\ \frac{1}{3}+k\pi\left(k\in Z\right)  

 x=π3+arcsin 13+kπ(kZ)x=\frac{\pi}{3}+\arcsin\ \frac{1}{3}+k\pi\left(k\in Z\right)  

 x=2π3arcsin 13+k2π(kZ)x=\frac{2\pi}{3}-\arcsin\ \frac{1}{3}+k2\pi\left(k\in Z\right)  và
 x=π3+arcsin 13+k2π(kZ)x=\frac{\pi}{3}+\arcsin\ \frac{1}{3}+k2\pi\left(k\in Z\right)  

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Phương trình

 2sin(3x)1=02\sin\left(3x\right)-1=0  có nghiệm là

 x=π9+k2π3(kZ)x=\frac{\pi}{9}+\frac{k2\pi}{3}\left(k\in Z\right)  và  x=5π9+k2π(kZ)x=\frac{5\pi}{9}+k2\pi\left(k\in Z\right)  

 x=±π18+k2π3(kZ)x=\pm\frac{\pi}{18}+\frac{k2\pi}{3}\left(k\in Z\right)  

 x=π18+k2π3(kZ) vaˋ  x=5π18+k2π3(kZ)x=\frac{\pi}{18}+\frac{k2\pi}{3}\left(k\in Z\right)\ và\ \ x=\frac{5\pi}{18}+\frac{k2\pi}{3}\left(k\in Z\right)  

 x=π18+k2π3(kZ) vaˋ  x=7π18+k2π3(kZ)x=-\frac{\pi}{18}+\frac{k2\pi}{3}\left(k\in Z\right)\ và\ \ x=\frac{7\pi}{18}+\frac{k2\pi}{3}\left(k\in Z\right)  

6.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Đâu là công thức nghiệm của phương trình sinx=1\sin x=1  

 x=π2+k2π,kZx=\frac{-\pi}{2}+k2\pi,k\in Z  

 x=π2+k2π,kZx=\frac{\pi}{2}+k2\pi,k\in Z  

 x=π2+kπ,kZx=\frac{\pi}{2}+k\pi,k\in Z  

 x=kπ,kZx=k\pi,k\in Z  

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Công thức nghiệm của phương trình


 sinx=sinα\sin x=\sin\alpha  là:

 x=α+k2π,kZx=\alpha+k2\pi,k\in Z  

 x=πα+k2π,kZx=\pi-\alpha+k2\pi,k\in Z  

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