4th Grade enVision Topic 2 Review

The table shows the number of parking spaces in three city lots.

Which shows the estimate of the total number of parking spaces found by rounding each number to the nearest hundred?

• 1,200 + 1,900 + 2,700 = 5,800

• 1,200 + 1,900 + 2,800 = 5,900

• 1,000 + 1,900 + 2,700 = 5,600

• 1,000 + 1,900 + 2,800 = 5,700

Tags

CCSS.4.NBT.A.1

CCSS.4.NBT.A.3

The table shows the number of parking spaces in three city lots.

What is the total number of parking paces?

• 3,181

• 5,900

• 5,937

• 5,927

Tags

CCSS.4.MD.A.2

CCSS.4.NBT.B.4

CCSS.4.OA.A.3

Find 7,000-3,290.

• 2,710

• 3,610

• 3,710

• 3,810

Tags

CCSS.4.NBT.B.4

Enter the missing digit to complete the subtraction.

• 0

• 6

• 5

• 4

Tags

CCSS.4.NBT.B.4

Find the difference.

• 9,152

• 1,932

• 9,290

• 7,574

Tags

CCSS.4.NBT.A.1

CCSS.4.NBT.B.4

Complete the equation. What number goes in the missing box?

• 33,529

• 16,347

• 17,182

• 600

Tags

CCSS.4.NBT.B.4

Find the difference.

• 3,283

• 16,883

• 3,385

• 3,000

Tags

CCSS.4.NBT.B.4

Which of the following statements is true? Select all that apply.

(There are two answers that are correct)

• 28,378 + 3,333 = 31,711

• 26,425 + 5,436 = 31,851

• 51,823 – 23,352 = 75,175

• 46,790 – 19,909 = 26,801

• 62,561 – 17,638 = 44,923

Tags

CCSS.4.NBT.B.4

Complete the sum.

• 10,267

• 9, 267

• 9,167

• 10, 167

Tags

CCSS.4.NBT.B.4

Lilly used addition properties to rewrite the equation below. Select all of the equations Lilly may have written.

2,090 + 3,250 + 1,350 = n

(Three choices are correct)

• 1,350 + 3,250 + 2,090 = n

• (2,090 + 3,250) + 1,350 = n

• 2,090 + (3,250) = n

• 3,250 + 1,350 + 0 = n

• 2,090 + 3,250 + 1,350 + 0 = n

Tags

CCSS.5.NBT.B.7

CCSS.5.OA.A.2