Taller Ev. Gráficas de movimiento. MRU - MRUV

Taller Ev. Gráficas de movimiento. MRU - MRUV

10th Grade

20 Qs

quiz-placeholder

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Taller Ev. Gráficas de movimiento. MRU - MRUV

Taller Ev. Gráficas de movimiento. MRU - MRUV

Assessment

Quiz

Physics

10th Grade

Hard

Created by

juan Carlos Bárcenas

Used 5+ times

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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

De acuerdo a las figuras, es incorrecto...

La fig.1 lleva velocidad constante mientras la fig.2, presentó variación

La fig.2 acelera y posteriormente la v = cte

La fig.1 es un ejemplo de MRU porque su v=cte

La fig.1 y fig.2 presentaron variación en la velocidad

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

La representación que se muestra a continuación es para el

MRUV

Caída libre

MCU

MRU

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

La representación que se muestra a continuación es para el

MRUV

Caída libre

MCU

MRU

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

La representación que se muestra a continuación es para el

velocidad constante

aumento de la velocidad

disminución en la velocidad

desaceleración

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

En base a la fig a) completa la b)

t0> 0 s; x0= 0 m; v = 0 mst_0>\ 0\ s;\ x_0=\ 0\ m;\ \ v\ =\ 0\ \frac{m}{s}

t0= 0 s; x0< 0 m; v < 0 mst_0=\ 0\ s;\ x_0<\ 0\ m;\ \ v\ <\ 0\ \frac{m}{s}

t0= 0 s; x0> 0 m; v > 0 mst_0=\ 0\ s;\ x_0>\ 0\ m;\ \ v\ >\ 0\ \frac{m}{s}

t0= 0 s; x0> 0 m; v < 0 mst_0=\ 0\ s;\ x_0>\ 0\ m;\ \ v\ <\ 0\ \frac{m}{s}

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

En base a la fig a) completa la b)

t0> 0 s; x0> 0 m; v > 0 ms(cte)t_0>\ 0\ s;\ x_0>\ 0\ m;\ \ v\ >\ 0\ \frac{m}{s}\left(cte\right)

t0= 0 s; x0< 0 m; v = 0 mst_0=\ 0\ s;\ x_0<\ 0\ m;\ \ v\ =\ 0\ \frac{m}{s}

t0= 0 s; x0> 0 m; v = 0 mst_0=\ 0\ s;\ x_0>\ 0\ m;\ \ v\ =\ 0\ \frac{m}{s}

t0= 0 s; x0> 0 m; v < 0 mst_0=\ 0\ s;\ x_0>\ 0\ m;\ \ v\ <\ 0\ \frac{m}{s}

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

En base a la fig a) completa la b)

t0> 0 s; x0> 0 m; v > 0 ms(cte)t_0>\ 0\ s;\ x_0>\ 0\ m;\ \ v\ >\ 0\ \frac{m}{s}\left(cte\right)

t0> 0 s; x0>0 m; v < 0 mst_0>\ 0\ s;\ x_0>0\ m;\ \ v\ <\ 0\ \frac{m}{s}

t0= 0 s; x0> 0 m; v = 0 mst_0=\ 0\ s;\ x_0>\ 0\ m;\ \ v\ =\ 0\ \frac{m}{s}

t0= 0 s; x0< 0 m; v < 0 mst_0=\ 0\ s;\ x_0<\ 0\ m;\ \ v\ <\ 0\ \frac{m}{s}

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