9 5.1 Trig Ratios

9 5.1 Trig Ratios

9th - 10th Grade

18 Qs

quiz-placeholder

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9 5.1 Trig Ratios

9 5.1 Trig Ratios

Assessment

Quiz

Mathematics

9th - 10th Grade

Hard

Created by

Mark Bugden

Used 9+ times

FREE Resource

18 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

The correct trig ratio linking the two labelled sides in the right-angled triangle shown is:

sin34°=25x\sin34\degree=\frac{25}{x}

\sin34\degree=\frac{x}{25}

tan34°=x25\tan34\degree=\frac{x}{25}

tan34°=25x\tan34\degree=\frac{25}{x}

cos34°=x25\cos34\degree=\frac{x}{25}

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

The correct trig ratio linking the two labelled sides in the right-angled triangle shown is:

tan40°=c12\tan40\degree=\frac{c}{12}

sin40°=c12\sin40\degree=\frac{c}{12}

cos40°=c12\cos40\degree=\frac{c}{12}

cos40°=12c\cos40\degree=\frac{12}{c}

sin40°=12c\sin40\degree=\frac{12}{c}

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

The correct trig ratio linking the two labelled sides in the right-angled triangle shown is:

sin20°=18q\sin20\degree=\frac{18}{q}

sin20°=q18\sin20\degree=\frac{q}{18}^{ }

cos20°=18p\cos20\degree=\frac{18}{p}

cos20°=q18\cos20\degree=\frac{q}{18}

tan20°=18q\tan20\degree=\frac{18}{q}^{ }

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

The correct trig ratio linking the two labelled sides in the right-angled triangle shown is:

cos60°=a2\cos60\degree=\frac{a}{2}

sin60°=a2\sin60\degree=\frac{a}{2}

tan60°=a2\tan60\degree=\frac{a}{2}

cos60°=2a\cos60\degree=\frac{2}{a}

tan60°=2a\tan60\degree=\frac{2}{a}^{ }

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

The correct trig ratio linking the two labelled sides in the right-angled triangle shown is:

tan28°=y15\tan28\degree=\frac{y}{15}

sin28°=y15\sin28\degree=\frac{y}{15}^{ }

tan28°=15y\tan28\degree=\frac{15}{y}

cos28°=y15\cos28\degree=\frac{y}{15}

cos28°=15y\cos28\degree=\frac{15}{y}^{ }

6.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

The correct trig ratio linking the two labelled sides in the right-angled triangle shown is:

tan26°=67p\tan26\degree=\frac{67}{p}

sin26°=p67\sin26\degree=\frac{p}{67}

tan26°=p67\tan26\degree=\frac{p}{67}

cos26°=p67\cos26\degree=\frac{p}{67}

cos26°=67p\cos26\degree=\frac{67}{p}^{ }

7.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

The correct trig ratio linking the two labelled sides in the right-angled triangle shown is:

sin32°=28r\sin32\degree=\frac{28}{r}

tan32°=r28\tan32\degree=\frac{r}{28}^{ }

cos32°=28r\cos32\degree=\frac{28}{r}

cos32°=r28\cos32\degree=\frac{r}{28}

tan32°=28r\tan32\degree=\frac{28}{r}^{ }

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