Ôn Lượng Giác 10 - Hè 2021 - TTT1310-

Ôn Lượng Giác 10 - Hè 2021 - TTT1310-

10th - 11th Grade

20 Qs

quiz-placeholder

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Ôn Lượng Giác 10 - Hè 2021 - TTT1310-

Ôn Lượng Giác 10 - Hè 2021 - TTT1310-

Assessment

Quiz

Mathematics, Other

10th - 11th Grade

Hard

Created by

LƯU DUY TÂN

Used 2+ times

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Ở góc phần tư thứ nhất của đường tròn lượng giác. Hãy chọn kết quả đúng trong các kết quả sau đây.

cotα<0\cot\alpha<0

sinα>0\sin\alpha>0

cosα<0\cos\alpha<0

tanα<0\tan\alpha<0

2.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Cho hai góc nhọn α\alpha  và β\beta phụ nhau. Hệ thức nào sau đây là sai?

 cotα=tanβ\cot\alpha=\tan\beta  

 cosα=sinβ\cos\alpha=\sin\beta  

 cosβ=sinα\cos\beta=\sin\alpha  

 cotβ=tanα\cot\beta=-\tan\alpha  

3.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Khẳng định nào sau đây đúng?


sin(x)=sinx\sin\left(-x\right)=-\sin x

cos(x)=cosx\cos\left(-x\right)=-\cos x

tan(x)=tanx\tan\left(-x\right)=\tan x

cot(x)=cotx\cot\left(-x\right)=\cot x

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Trên hình vẽ hai điểm M, N biểu diễn các cung có số đo là:

 x=π3+k2πx=\frac{\pi}{3}+k2\pi  

 x=π3+kπx=-\frac{\pi}{3}+k\pi  

 x=π3+kπx=\frac{\pi}{3}+k\pi  

 x=π3+k2πx=-\frac{\pi}{3}+k2\pi  

5.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

 cos(x+2017π)=?\cos\left(x+2017\pi\right)=?  

 cosx-\cos x  

 sinx-\sin x  

 sinx\sin x  

 cosx\cos x  

6.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Trong các công thức sau, công thức nào ĐÚNG?

cos(ab)=cosa.sinb+sina.cosb\cos\left(a-b\right)=\cos a.\sin b+\sin a.\cos b

sin(ab)=sina.cosbcosa.sinb\sin\left(a-b\right)=\sin a.\cos b-\cos a.\sin b

sin(a+b)=sina.cosbcosa.sinb\sin\left(a+b\right)=\sin a.\cos b-\cos a.\sin b

cos(a+b)=cosa.cosb+sina.sinb\cos\left(a+b\right)=\cos a.\cos b+\sin a.\sin b

7.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Chọn khẳng định SAI trong các khẳng định sau:


cos(a+b)=cosa.cosb+sina.sinb\cos\left(a+b\right)=\cos a.\cos b+\sin a.\sin b

sin(a+b)=sina.cosb+cosa.sinb\sin\left(a+b\right)=\sin a.\cos b+\cos a.\sin b

sin(ab)=sina.cosbcosa.sinb\sin\left(a-b\right)=\sin a.\cos b-\cos a.\sin b

cos2a=12sin2a\cos2a=1-2\sin^2a

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