Motion_3

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h⁻¹ in 10 minutes. Find its acceleration. What is the first information give?

• The initial velocity of the train (u) =0

• Final velocity of the train (v)=40 km/h = 11.11 m/s

• Time taken(t) =10 min= 600s

• Acceleration is given by

  = Change in speed/ time taken

• = (v-u)/t

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h⁻¹ in 10 minutes. Find its acceleration. What is the second information give?

• = .0185 m/s²

• Final velocity of the train (v)=40 km/h = 11.11 m/s

• Time taken(t) =10 min= 600s

• Acceleration is given by

  = Change in speed/ time taken

• = (v-u)/t

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h⁻¹ in 10 minutes. Find its acceleration. What is the thirdinformation give?

• = .0185 m/s²

• Final velocity of the train (v)=40 km/h = 11.11 m/s

• Time taken(t) =10 min= 600s

• Acceleration is given by

  = Change in speed/ time taken

• = (v-u)/t

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h⁻¹ in 10 minutes. Find its acceleration. What will you calculate and how will you calculate?

• = .0185 m/s²

• Final velocity of the train (v)=40 km/h = 11.11 m/s

• Time taken(t) =10 min= 600s

• Acceleration is given by

  = Change in speed/ time taken

• = (v-u)/t

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h⁻¹ in 10 minutes. Find its acceleration. which formula will you apply?

• = .0185 m/s²

• Final velocity of the train (v)=40 km/h = 11.11 m/s

• Time taken(t) =10 min= 600s

• Acceleration is given by

  = Change in speed/ time taken

• = (v-u)/t

A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h⁻¹ in 10 minutes. Find its acceleration. what is your answer?

• = .0185 m/s²

• Final velocity of the train (v)=40 km/h = 11.11 m/s

• Time taken(t) =10 min= 600s

• Acceleration is given by

  = Change in speed/ time taken

• = (v-u)/t

What is the nature of the distance - 'time graphs for uniform and non-uniform motion of an object?

• When the motion is uniform, the distance time graph is a straight line with a slope.

• When the motion is non uniform, the distance time graph is not a straight line. It can be any curve.

What is the nature of the distance - 'time graphs for uniform and non-uniform motion of an object?

• When the motion is uniform, the distance time graph is a straight line with a slope.

• When the motion is non uniform, the distance time graph is not a straight line. It can be any curve.

What can you say about the motion of an object whose distance-time graph is a straight line parallel to the time axis?

• It is at rest

• It is moving at a constant speed

• moving at constant velocity

• moving n a straight line

What can you say about the motion of an object if its speed - 'time graph is a straight line parallel to the time axis?

• It means speed is constant and object is moving uniformly

• It means position changes with time

• It means the object is stationary

• A body is said to be at rest