Algebra 2 EOC

Solve $v=u+at$  for  $a$  

•  $a=\left(v-u\right)t$  

•  $a=v-at$  

•  $a=\frac{v-u}{t}$  

• No real solution

Tags

CCSS.HSA.CED.A.4

Solve  $V=\pi r^2h$  for  $r$  

•  $r=\sqrt{\frac{V}{\pi h}}$  

•  $r=\left(\frac{V}{\pi h}\right)^2$  

•  $r=\frac{V}{\pi hr}$  

•  $r=\left(v\pi h\right)^2$  

Tags

CCSS.HSA.CED.A.4

Solve $A=\frac{r}{2L}$  for  $L$  

•  $L=\frac{2A}{r}$  

•  $L=\frac{r}{2A}$  

•  $L=2Ar$  

•  $AL=2r$  

Tags

CCSS.HSA.CED.A.4

The equation of the line is:

• $y=2x-3$

• $y=-2x+3$

• $y=2x+3$

• $y==\frac{1}{2}x+3$

The equation of a line whose slope is 7 and passes through the point (1, 2) is

• y = -7x + 9

• y = 7x- 5

• y = 7x - 9

• y = 7x + 5

Given $y=-\frac{1}{3}x+4$ The equation of a line that is perpendicular and passing through  $\left(1,-4\right)$  is:

•  $y=3x-7$  

•  $y=\frac{1}{3}x+7$  

•  $y=-3x+1$  

•  $y=-\frac{1}{3}x-7$  

The equation of a line parallel to $y=\frac{7}{11}x-2$  and passing through the origin is:

•  $y=7x+13$  

•  $y=\frac{7}{11}x+2$  

•  $y=\frac{11}{7}x-2$  

•  $y=\frac{7}{11}x$ 

The slope of the line is:

• $0$

• $1$

• Undefined

• $-1$

Tags

CCSS.8.EE.B.5

The solution for this system of equations is

• (3, 2)

• (2, 3)

• (-4, 0)

• (5, 0)

Tags

CCSS.8.EE.C.8B

y = −3x + 5

5x − 4y = −3

The solution for this system is

• (1, 2)

• (2, 1)

• (1, -2)

• (2, -1)

Tags

CCSS.HSA.REI.C.6

CCSS.8.EE.C.8B