Algebra 2 EOC

Algebra 2 EOC

9th - 11th Grade

30 Qs

quiz-placeholder

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Algebra 2 EOC

Algebra 2 EOC

Assessment

Quiz

Mathematics

9th - 11th Grade

Hard

CCSS
HSA.APR.D.6, HSA.CED.A.4, 8.EE.C.8B

+7

Standards-aligned

Created by

Arthur McIntosh

Used 16+ times

FREE Resource

30 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve v=u+atv=u+at  for  aa  

 a=(vu)ta=\left(v-u\right)t  

 a=vata=v-at  

 a=vuta=\frac{v-u}{t}  

No real solution

Tags

CCSS.HSA.CED.A.4

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve  V=πr2hV=\pi r^2h  for  rr  

 r=Vπhr=\sqrt{\frac{V}{\pi h}}  

 r=(Vπh)2r=\left(\frac{V}{\pi h}\right)^2  

 r=Vπhrr=\frac{V}{\pi hr}  

 r=(vπh)2r=\left(v\pi h\right)^2  

Tags

CCSS.HSA.CED.A.4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve A=r2LA=\frac{r}{2L}  for  LL  

 L=2ArL=\frac{2A}{r}  

 L=r2AL=\frac{r}{2A}  

 L=2ArL=2Ar  

 AL=2rAL=2r  

Tags

CCSS.HSA.CED.A.4

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

The equation of the line is:

y=2x3y=2x-3

y=2x+3y=-2x+3

y=2x+3y=2x+3

y==12x+3y==\frac{1}{2}x+3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The equation of a line whose slope is 7 and passes through the point (1, 2) is

y = -7x + 9

y = 7x- 5

y = 7x - 9

y = 7x + 5

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given y=13x+4y=-\frac{1}{3}x+4 The equation of a line that is perpendicular and passing through  (1,4)\left(1,-4\right)  is:

 y=3x7y=3x-7  

 y=13x+7y=\frac{1}{3}x+7  

 y=3x+1y=-3x+1  

 y=13x7y=-\frac{1}{3}x-7  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The equation of a line parallel to y=711x2y=\frac{7}{11}x-2  and passing through the origin is:

 y=7x+13y=7x+13  

 y=711x+2y=\frac{7}{11}x+2  

 y=117x2y=\frac{11}{7}x-2  

 y=711xy=\frac{7}{11}x 

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