Right Triangles and the Pythagorean Theorem

Right Triangles and the Pythagorean Theorem

8th Grade

8 Qs

quiz-placeholder

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Right Triangles and the Pythagorean Theorem

Right Triangles and the Pythagorean Theorem

Assessment

Quiz

Mathematics

8th Grade

Medium

CCSS
8.G.B.8, 2.G.A.1, HSG.CO.C.10

+1

Standards-aligned

Created by

Grace Penhallegon

Used 29+ times

FREE Resource

8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does every right triangle have?

a 90 degree angle

3 sides of the same length

2 sides of the same length

2 angles of the same measure

Tags

CCSS.2.G.A.1

2.

MULTIPLE SELECT QUESTION

45 sec • 1 pt

What is true about the hypotenuse?


Check all that apply

It is the longest side

It is the shortest side

It is next to the 90 degree angle

It is opposite from the 90 degree angle

Tags

CCSS.HSG.CO.C.10

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which letter is used to represent the hypotenuse?

a

b

c

4.

MULTIPLE SELECT QUESTION

45 sec • 1 pt

What is true about the legs of a right triangle?


Check all that apply

They are the longest sides

They are the shorter sides

They are opposite the 90 degree angle.

They are next to the 90 degree angle.

5.

MULTIPLE SELECT QUESTION

45 sec • 1 pt

Which letter(s) are used to represent the legs of a right triangle?


Check all that apply.

a

b

c

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the pythagorean theorem?

a2 + b2 = c2

a2 - b2 = c2

a2 + b2 + c2

a2 + c2 = b2

Tags

CCSS.8.G.B.8

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The pythagorean theorem can be used to find the missing side of any type of triangle.

True

False

Tags

CCSS.8.G.B.8

8.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

a = 3

b = 4

c = ?


Which option correctly uses the pythagorean theorem to solve of the hypotenuse?

a2 + b2 = c2

32 + 42 = c2

9 + 16 = c2

25 = c2

5 = c

a2 + b2 = c2

32 + 42 = c2 

6 + 8 = c2

14 = c2

c = √14

a2 + b2 = c2

32 + 42 = c2

9 + 16 = c2

20 = c2

c = √20

a2 + b2 = c2

42 + b2 = 32

16 + b2 = 9

b2 = 9 - 16

b2 = -5

Tags

CCSS.8.G.B.7