Integrales por sustitución

Integrales por sustitución

12th Grade

7 Qs

quiz-placeholder

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Integrales por sustitución

Integrales por sustitución

Assessment

Quiz

Mathematics

12th Grade

Medium

Created by

LILIAN RODRIGUEZ

Used 19+ times

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7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 (2x5)10 dx =\int_{ }^{ }\left(2x-5\right)^{10}\ dx\ =  

 (2x5)1111+C\frac{\left(2x-5\right)^{11}}{11}+C  

 (2x5)99+C\frac{\left(2x-5\right)^9}{9}+C  

 (2x5)918+C\frac{\left(2x-5\right)^9}{18}+C  

 (2x5)1122+C\frac{\left(2x-5\right)^{11}}{22}+C  

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 x5+2x2  dx =             + C\int_{ }^{ }x\sqrt{5+2x^2}\ \ dx\ =\ \ \ \ \ \ \ \ \ \ \ \ \ +\ C  

 16(5+2x2)32\frac{1}{6}\left(5+2x^2\right)^{\frac{3}{2}}  

 2(5+2x2)122\left(5+2x^2\right)^{\frac{1}{2}}  

 23(5+2x2)32\frac{2}{3}\left(5+2x^2\right)^{\frac{3}{2}}  

 14(5+2x2)32\frac{1}{4}\left(5+2x^2\right)^{\frac{3}{2}}  

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 e2x dx=     +C\int_{ }^{ }e^{2x}\ dx=\ \ \ \ \ +C  

 12eu\frac{1}{2}e^u  

 12e2x\frac{1}{2}e^{2x}  

 e2xe^{2x}  

 2e2x2e^{2x}  

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 x cos(5x2) dx =      +C\int_{ }^{ }x\ \cos\left(5x^2\right)\ dx\ =\ \ \ \ \ \ +C  

 110sin(5x2)\frac{1}{10}\sin\left(5x^2\right)  

 25sin(5x2)\frac{2}{5}\sin\left(5x^2\right)  

 110cos(5x2)\frac{1}{10}\cos\left(5x^2\right)  

 110sin(5x2)-\frac{1}{10}\sin\left(5x^2\right)  

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 x3 ex4  dx =      +C\int_{ }^{ }x^3\ e^{x^4}\ \ dx\ =\ \ \ \ \ \ +C  

 14ex4\frac{1}{4}e^{x^4}  

 4 ex4\ e^x  

 ex4e^{x^4}  

 12ex4\frac{1}{2}e^{x^4}  

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

   6x(5+3x2)4dx=     +C\int_{ }^{ }\ \ \frac{6x}{\left(5+3x^2\right)^4}dx=\ \ \ \ \ +C  

 13(5+3x2)3-\frac{1}{3\left(5+3x^2\right)^3}  

 1(5+3x2)3\frac{1}{\left(5+3x^2\right)^3}  

 161(5+3x2)3-\frac{1}{6}\frac{1}{\left(5+3x^2\right)^3}  

 13(6x)3-\frac{1}{3\left(6x\right)^3}  

7.

FILL IN THE BLANK QUESTION

5 mins • 1 pt

 01 2x (1x2) dx = \int_0^1\ 2x\ \left(1-x^2\right)\ dx\ =\