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Assessing Normality

Authored by Kelly Downs

Mathematics

11th - 12th Grade

CCSS covered

Used 21+ times

Assessing Normality
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16 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If a graph of quantitative data looks symmetric, single peaked, and bell-shaped, then the distribution is approximately normal. We don't need to check anything else.

True

False

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the mean and median of a data set are roughly equal, then the data is probability symmetric, but not necessarily normal.

True

False

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Does this dotplot lead you to believe that the distribution is approximately normal?

Yes, the graph is symmetrical, single peaked and bell-shaped.

No, the graph is skewed right.

No, the graph is skewed left.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Here are the ages of 10 people at a party. 14 14 18 18 19 21 35 42 65 80 Calculate the mean and median using a statistical calculator or by hand. Are they close?

Mean = 20, Median = 32.6 They are not close

Mean = 35, Median = 19 They are not close

Mean = 31, Median = 29 They are close

Mean = 32.6, Median = 20 They are not close

Mean = 19.8, Median = 21 They are close

Tags

CCSS.6.SP.B.5C

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Here are the ages of 10 people at a party. 14 14 18 18 19 21 35 42 65 80 In the last question, the mean was found to be 32.6 and the median was 20. Since the mean is quite a bit higher than the median, what is most likely the shape of the distribution of ages?

Symmetric

Uniform

Skewed Left

Skewed Right

Tags

CCSS.6.SP.B.5D

CCSS.HSS.ID.A.2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Here are the ages of 10 people at a party. 14 14 18 18 19 21 35 42 65 80 In your notebook, make a dot plot of the data. What shape does it have? Note: This answer should be the same as the last question!

Symmetric

Skewed Left

Skewed Right

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The following data set of 10 values has a mean = 10 and a SD = 6.77 2 2 4 4 10 10 15 15 19 19 Create the interval MEAN +/- 1 SD by subtracting 6.77 from the10 to get the low end and then adding 6.77 to 10 to get the high end.

3.23 to 16.77

3.54 to 9.56

2.15 to 10.28

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