Compound Probability

Compound Probability

9th - 12th Grade

10 Qs

quiz-placeholder

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Compound Probability

Compound Probability

Assessment

Quiz

Mathematics

9th - 12th Grade

Hard

CCSS
HSS.CP.B.7

Standards-aligned

Created by

Mr. Casilli

Used 19+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

If two events A and B are disjoint, meaning they CANNOT happen at the same time, what is P(A or B)?

 P(A)P(B)P(A)-P(B)  

 P(A)P(B)P(A)\cdot P(B)  

 P(A)+P(B)P(A)+P(B)  

 P(A)P(B)\frac{P(A)}{P(B)}  

Tags

CCSS.HSS.CP.B.7

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

If two events A and B are NOT disjoint, meaning they CAN happen at the same time, what is P(A or B)?

 P(A)P(B)+P(AandB)P(A)-P(B)+P\left(AandB\right)  

 P(A)P(B)P(AandB)P(A)\cdot P(B)-P\left(AandB\right)  

 P(A)+P(B)P(AandB)P(A)+P(B)-P\left(AandB\right)  

 P(A)P(B)+P(AandB)\frac{P(A)}{P(B)}+P\left(AandB\right)  

Tags

CCSS.HSS.CP.B.7

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

A spinner with 5 colors is spun and a 6-sided die is rolled. How many outcomes are in the sample space?

2

11

24

30

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

A teacher wanted to know the probability of selecting a student at random that either plays sports OR has blond hair. The teacher counted ALL of the students that play sports and then ALL of the students with blond hair, and added the totals together. What did the teacher do wrong?

He didn't count the students with dark hair.

He undercounted the students who play sports and have blond hair.

He overcounted the students who play sports and have blond hair.

He didn't ask the students what sports they play.

Tags

CCSS.HSS.CP.B.7

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

What is P(K or 5)?

452=113\frac{4}{52}=\frac{1}{13}

852=213\frac{8}{52}=\frac{2}{13}

1652=413\frac{16}{52}=\frac{4}{13}

952\frac{9}{52}

Tags

CCSS.HSS.CP.B.7

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

What is P(heart or 4)?

 1352=14\frac{13}{52}=\frac{1}{4} 

 3052=1526\frac{30}{52}=\frac{15}{26} 

1652=413\frac{16}{52}=\frac{4}{13}

 1752\frac{17}{52} 

Tags

CCSS.HSS.CP.B.7

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

What is P(black or 7)?

 2652=12\frac{26}{52}=\frac{1}{2} 

 3052=1526\frac{30}{52}=\frac{15}{26} 

 2852=713\frac{28}{52}=\frac{7}{13} 

 3252=813\frac{32}{52}=\frac{8}{13} 

Tags

CCSS.HSS.CP.B.7

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