iav ML Study Group Pop Quiz 4

In Python, a dictionary consists of:

• Key:Value pairs

• Value:Key pairs

• Translation maps

• Languange<->Language encodings

Given a dictionary: testdict

Write the command to see all keys from the dictionary

Select the methods which will REMOVE the number 4 from the list:

numlist=[1,2,3,4]

• numlist.drop(4)

• numlist.drop(3)

• numlist.pop(3)

• numlist.pop()

Which is the expected output from:

test_tuple("red","green","blue")

test_tuple[1]= "pink"

print(test_tuple)

• ("red","pink","blue")

• ("pink","green","blue")

• test_tuple

• TypeError: 'tuple' object does not support item assignment

Defining your own custom data classes instead of using the defaults has the advantages of:

• shortening the syntax for variable instantiation

• pretty-printing the string representation with .__repr__()

• self-documentation with type annotation

• faster loading times

The difference between tuples and namedtuples is that

• namedtuples are mutable

• tuples cannot be named

• namedtuple elements can be accessed through an identifier instead of just the index position

• tuples don't exist as a native class in Python

We instantiate a set with:

• Brackets, ()

• Square Brackets, []

• Curly Brackets, {}

• Double Quotes: " "

For the last 3 questions, assume we have Set X and Set Y.

I want to find the new set, XuY which contains all distinct elements in BOTH X and Y. The syntax would be:

• XuY = X.union(Y)

• XuY = Y.union(X)

• XuY = VennUnion(X,Y)

• XuY = numpy.union(X,Y)

I want a new set XintY which contains all of the elements present in BOTH X and Y. The syntax is:

• XintY = X.intersection(Y)

• XintY = Y.intersection(X)

• XintY = VennIntersection(X,Y)

• XintY = numpy.intersection(X,Y)

I want to see if X is a superset of Y. That is, whether at least EVERY element in Y is also an element in X. The syntax is:

• X.superset(Y)

• Y.superset(X)

• VennMath.advanced.complex.superset_check(X,Y)

• X > Y