Factoring and Quadratic Part 2

 $Consider\ the\ quadratic\ equation\ \ \ \ \ x^2-3x-10\ =\ 0$  Name the a, b and c of the equation.

 $\sqrt{b^2-4\alpha c}$  

Evaluate the expression with the given equation:

 $x^2-2x-2\ =\ 0$  

Factor:

56a³ - 8a

• 8a²(56a³-8a)

• 8a (7a²-1)

• 8a(7a³-a)

• 8a²(35a²-a)

Factor x² - 2x -15

• (x+5)(x-3)

• (x-5)(x-3)

• (x-5)(x+3)

• (x+5)(x+3)

What is the first step when factoring polynomials?

• Find the GCF

• List all the terms

• Make the X and fill in the top and bottom

• Multiply a and c

Factor using GCF or monomial factoring:

2n²- 8n³

• 2n²(n-4n²)

• 2n²(1-4n)

• 2n³(10-8n²)

• 3n(1-4n)

Determine the values of

a, b, and c for

the quadratic equation:

4x² – 8x = 3

• a = 4, b = -8, c = 3

• a = 4, b =-8, c =-3

• a = 4, b = 8, c = 3

• a = 4, b = 8, c = -3

The discriminant is

• aX²  + bX  +  c
• b - 4ac
• b² - 4ac
• b² + 4ac

Factor 6x² - 27x

• (6x+1)(x+3)

• 3x(2x-9)

• 6x(x-9)

• (3x-9)(2x+3)

Factor:

2n³ + 16n +12

• 2n(n³+24n+6)

• 2(n³+8n+6)

• 2n(n³+8n+6)

• 3(n³+8n+6)