Chapter 6 Ratios and Graphs of Trigonometric Functions

Chapter 6 Ratios and Graphs of Trigonometric Functions

10th - 12th Grade

10 Qs

quiz-placeholder

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Chapter 6 Ratios and Graphs of Trigonometric Functions

Chapter 6 Ratios and Graphs of Trigonometric Functions

Assessment

Quiz

Mathematics

10th - 12th Grade

Hard

Created by

Cg Intan Syazwanie Mohd Sulaiman

Used 98+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

In the diagram above, QRS is a straight line. Find the value of cos x.

Dalam rajah di atas, QRS ialah garis lurus. Cari nilai kos x.

1517-\frac{15}{17}

817-\frac{8}{17}

817\frac{8}{17}

1517\frac{15}{17}

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

The diagram above shows the graph of y = cos x. Find the value of p.

Rajah di atas menunjukkan graf bagi y = kos x. Cari nilai p.

90°

180°

270°

360°

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

21

25

28

30

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

In the diagram above, BCD is a straight line. Find the value of cos x.

Dalam rajah di atas, BCD ialah garis lurus. Cari nilai kos x

1213-\frac{12}{13}

513-\frac{5}{13}

512-\frac{5}{12}

125-\frac{12}{5}

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Which of the following graphs represents y = sin 2x?

Antara yang berikut, yang manakah mewakili graf y = sin 2x?

Media Image
Media Image
Media Image
Media Image

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Given that cos θ = –0.6611 and 180° ≤ θ ≤ 360°, find the value of θ.

Diberi bahawa kos θ = –0.6611 dan 180° ≤ θ ≤ 360°, cari nilai θ.

131°23ʹ

138°37ʹ

221°23ʹ

228°37ʹ

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

In the diagram above, KLM is a right-angled triangle. It is given that KM = 17 cm, JL = 30 cm and K is the midpoint of JL. Find the value of tan y.

Dalam rajah di atas, KLM ialah sebuah segi tiga bersudut tegak. Diberi bahawa KM = 17 cm, JL = 30 cm dan K ialah titik tengah bagi JL. Cari nilai tan y.

817-\frac{8}{17}

815-\frac{8}{15}

158-\frac{15}{8}

178-\frac{17}{8}

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