A → = 6 m a t 35 ° \overrightarrow{A}=6m\ at\ 35\degree A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 6 m a t 3 5 ° from the positive x axis counter clock wise and B → = 8 m a t 45 ° \overrightarrow{B}=\ 8m\ at\ 45\degree B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 8 m a t 4 5 ° from the positive x axis clockwise. Find R → \overrightarrow{R} R <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

R → = 10.80 m a t 11.86 ° f r o m p o s i t i v e x a x i s c l o c k w i s e \overrightarrow{R}=10.80m\ at\ 11.86\degree\ from\ positive\ x\ axis\ clockwise R <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 1 0 . 8 0 m a t 1 1 . 8 6 ° f r o m p o s i t i v e x a x i s c l o c k w i s e

R → = 10.80 m a t 11.86 ° f r o m p o s i t i v e x a x i s c o u n t e r c l o c k w i s e \overrightarrow{R}=10.80\ m\ at\ 11.86\degree\ from\ positive\ x\ axis\ counterclockwise R <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 1 0 . 8 0 m a t 1 1 . 8 6 ° f r o m p o s i t i v e x a x i s c o u n t e r c l o c k w i s e

R → = 13.95 m a t 40.73 ° f r o m p o s i t i v e x a x i s c o u n t e r c l o c k w i s e \overrightarrow{R}=13.95m\ at\ 40.73\degree\ from\ positive\ x\ axis\ counterclockwise R <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 1 3 . 9 5 m a t 4 0 . 7 3 ° f r o m p o s i t i v e x a x i s c o u n t e r c l o c k w i s e

R → = 13.95 m a t 40.73 ° f r o m p o s i t i v e x a x i s c l o c k w i s e \overrightarrow{R}=13.95m\ at\ 40.73\degree\ from\ positive\ x\ axis\ clockwise R <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 1 3 . 9 5 m a t 4 0 . 7 3 ° f r o m p o s i t i v e x a x i s c l o c k w i s e

A → = 11 m a t 60 ° \overrightarrow{A}=11m\ at\ 60\degree A <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 1 1 m a t 6 0 ° and B → = 8 m a t 280 ° \overrightarrow{B}=8m\ at\ 280\degree B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 8 m a t 2 8 0 ° both from the positive x axis. Find R → \overrightarrow{R} R <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> you can write your answer as (ex. R=11m at 60degrees, from positive x axis)

R=7.08m at 13.47degrees, from positive x axis

R= 7.08m at 13.47degrees, from positive x axis

T w o f o r c e s a c t o n a p a r t i c l e F 1 → = 2 i + 3 j − 5 k Two\ forces\ act\ on\ a\ particle\ \overrightarrow{F_1}=2i+3j-5k T w o f o r c e s a c t o n a p a r t i c l e F 1 <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 2 i + 3 j − 5 k and F 2 → = − 5 i + j + 5 k \overrightarrow{F_2}=\ -5i+j+5k F 2 <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = − 5 i + j + 5 k . Find the resultant of the forces, and its magnitude.

resultant = -3i+4j, magnitude =5

resultant = 3i+4j, magnitude =5

resultant = 3i+4j, magnitude =25

resultant = -3i+4j, magnitude =25

Chapter Quiz(Intro)

Authored by Angelica Baral

Physics

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MULTIPLE CHOICE QUESTION

1 min • 1 pt

On one of the express way in the Philippines, a car travelled at a speed of 38m/s. Covert it to mi/hr. Suppose the speed limit on that express way is 60mi/hr. Is this car exceeding the speed limit?

16.98 mi/hr. , it does not exceed the speed limit.

76.56 mi/hr. , it exceed the speed limit.

58.43 mi/hr. , it does not exceed the speed limit

85.02 mi/hr. , it exceed the speed limit

FILL IN THE BLANK QUESTION

20 sec • 1 pt

Express the following quantities using prefixes(symbol)
round to the nearest tenths
$3.39\times10^{-3}m$

FILL IN THE BLANK QUESTION

20 sec • 1 pt

Express the following quantities using prefixes(symbol)
round to the nearest tenths
$2.74\times10^{-12}m$

FILL IN THE BLANK QUESTION

20 sec • 1 pt

Express the following quantities using prefixes
round to the nearest tenths
$5.38\times10^{-6}s$

FILL IN THE BLANK QUESTION

20 sec • 1 pt

Express the following quantities using prefixes(symbol)
round to the nearest tenths

$4.44\times10^6g$

FILL IN THE BLANK QUESTION

20 sec • 1 pt

Express the following quantities using prefixes(symbol)
round to the nearest tenths

$1.736\times10^{12}B$

FILL IN THE BLANK QUESTION

3 mins • 1 pt

The volume of a wallet is $8.48\ in.^3$ . Convert this value to $m^3$ (in standard form). round to the nearest tenths

Example: 8.5 x 10^-6 in^3 (write your answer like this)

FILL IN THE BLANK QUESTION

3 mins • 1 pt

A rectangular building lot is 110ft by 160ft. Determine the area of this lot in $m^2$ final answer must be rounded to the nearest one

example: 2345m^2 (write your answer like this)

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Chapter Quiz(Intro)

On one of the express way in the Philippines, a car travelled at a speed of 38m/s. Covert it to mi/hr. Suppose the speed limit on that express way is 60mi/hr. Is this car exceeding the speed limit?

Express the following quantities using prefixes(symbol)
round to the nearest tenths
$3.39\times10^{-3}m$

Express the following quantities using prefixes(symbol)
round to the nearest tenths
$2.74\times10^{-12}m$

Express the following quantities using prefixes
round to the nearest tenths
$5.38\times10^{-6}s$

Express the following quantities using prefixes(symbol)
round to the nearest tenths

$4.44\times10^6g$

Express the following quantities using prefixes(symbol)
round to the nearest tenths

$1.736\times10^{12}B$

The volume of a wallet is $8.48\ in.^3$ . Convert this value to $m^3$ (in standard form). round to the nearest tenths

Example: 8.5 x 10^-6 in^3 (write your answer like this)

A rectangular building lot is 110ft by 160ft. Determine the area of this lot in $m^2$ final answer must be rounded to the nearest one

example: 2345m^2 (write your answer like this)

A solid piece of lead has a mass of 23.94g and a volume of 2.10cm^3. Calculate the density of lead in SI units (kg/m^3). Note: convert first into SI units
density=mass/volume

do not include (,) in your answers, numbers and units only ex.(1234kg/m^3)

Suppose Ben measured the length of a wooden block 3 times and arrived with these measurements (21.7mm, 22.3mm, 21.8mm) What is the average of the measurements including its uncertainty?

you can write this as (Ex. 30.1mm±0.4mm) or (30.1mm+_0.4mm)

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Physics

Chapter Quiz(Intro)

On one of the express way in the Philippines, a car travelled at a speed of 38m/s. Covert it to mi/hr. Suppose the speed limit on that express way is 60mi/hr. Is this car exceeding the speed limit?

Express the following quantities using prefixes(symbol)*round to the nearest tenths* 3.39×10−3m3.39\times10^{-3}m3.39×10−3m

Express the following quantities using prefixes(symbol)*round to the nearest tenths* 2.74×10−12m2.74\times10^{-12}m2.74×10−12m

Express the following quantities using prefixes*round to the nearest tenths* 5.38×10−6s5.38\times10^{-6}s5.38×10−6s

Express the following quantities using prefixes(symbol)*round to the nearest tenths* 4.44×106g4.44\times10^6g4.44×106g

Express the following quantities using prefixes(symbol)*round to the nearest tenths* 1.736\times10^{12}B1.736×1012B

The volume of a wallet is 8.48 in.38.48\ in.^38.48 in.3 . Convert this value to m3m^3m3 (in standard form). *round to the nearest tenths*Example: 8.5 x 10^-6 in^3 (write your answer like this)

A rectangular building lot is 110ft by 160ft. Determine the area of this lot in m^2m2 *final answer must be rounded to the nearest one*example: 2345m^2 (write your answer like this)

A solid piece of lead has a mass of 23.94g and a volume of 2.10cm^3. Calculate the density of lead in SI units (kg/m^3). Note: convert first into SI units*density=mass/volume*do not include (,) in your answers, numbers and units only ex.(1234kg/m^3)

Suppose Ben measured the length of a wooden block 3 times and arrived with these measurements (21.7mm, 22.3mm, 21.8mm) What is the average of the measurements including its uncertainty? you can write this as (Ex. 30.1mm±0.4mm) or (30.1mm+_0.4mm)

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Physics

Express the following quantities using prefixes(symbol)
round to the nearest tenths
$3.39\times10^{-3}m$

Express the following quantities using prefixes(symbol)
round to the nearest tenths
$2.74\times10^{-12}m$

Express the following quantities using prefixes
round to the nearest tenths
$5.38\times10^{-6}s$

Express the following quantities using prefixes(symbol)
round to the nearest tenths

$4.44\times10^6g$

Express the following quantities using prefixes(symbol)
round to the nearest tenths

$1.736\times10^{12}B$

The volume of a wallet is $8.48\ in.^3$ . Convert this value to $m^3$ (in standard form). round to the nearest tenths

Example: 8.5 x 10^-6 in^3 (write your answer like this)

A rectangular building lot is 110ft by 160ft. Determine the area of this lot in $m^2$ final answer must be rounded to the nearest one

example: 2345m^2 (write your answer like this)

A solid piece of lead has a mass of 23.94g and a volume of 2.10cm^3. Calculate the density of lead in SI units (kg/m^3). Note: convert first into SI units
density=mass/volume

do not include (,) in your answers, numbers and units only ex.(1234kg/m^3)

Suppose Ben measured the length of a wooden block 3 times and arrived with these measurements (21.7mm, 22.3mm, 21.8mm) What is the average of the measurements including its uncertainty?

you can write this as (Ex. 30.1mm±0.4mm) or (30.1mm+_0.4mm)