8.5 A2

To solve 36 = 6^x, re-write 36 as what base and exponent?

• 3⁶

• 6³

• 6²

• 3¹²

To solve for x in the problem below, which equation would you use?

  $36=6^{\left(x+1\right)}$ , 

•  $36=x+1$  

•  $36=6^x+6$  

•  $x+1=2$  

•  $36=6x+6$  

 $3^3=3^{\left(4x+2\right)}$  To solve the equation below, it is important you ________

• have the same bases before setting the exponents equal to each other.

• have the same exponents before setting the bases equal to each other.

• find the value of  $3^3$  first.

• distribute the across the parantheses for  $3^{\left(4x+2\right)}$  

Solve the equation below for x.


 $3^3=3^{\left(4x+2\right)}$  

•  $-\frac{1}{4}$  

•  $\frac{1}{4}$  

•  $-\frac{5}{4}$  

•  $\frac{5}{4}$  

Solve for n:
2^-2n = 2⁶

• -1
• -7
• 5
• -3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.1

To solve this exponential equation
 $3^x=2$  
 which cannot be changed into the same bases on both sides of the equal sign, you must _________________

• raise 2 to the power of x also.

• set x = 2

• divide by 3.

• take the logarithm of both sides.

Which statement is a step in the process of solving the following exponential equation for x.
 $3^{\left(x+1\right)}=2$ 

•  $3^{\left(x+1\right)}=\log2$ 

•  $\left(x+1\right)\log3=2$ 

•  $\left(x+1\right)\log3=\log2$ 

•  $x+1=\log2-\log3$ 

Write in logarithm form
 $6^{-3}=\frac{1}{216}$  

•  $\log_6\ -3=\frac{1}{216}$  

•  $\log_{-3}\ 6=\frac{1}{216}$  

•  $\log_6\ \frac{1}{216}=-3$  

•  $\log_{\frac{1}{216}}\ 6=-3$ 

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

The basic requirement in solving the exponential equations is

• the base in both exponentials has to be the same

• the exponents of the equations are the same.

• the base in both exponents has to be different.

• the exponents of the equations have to be different.

To solve 8 = 2^5x+7, you would need to re-write 8 as what base?

• 8

• 4

• 2

• Cannot be determined