Persamaan Lingkaran

Persamaan Lingkaran

12th Grade

10 Qs

quiz-placeholder

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Persamaan Lingkaran

Persamaan Lingkaran

Assessment

Quiz

Mathematics

12th Grade

Medium

Created by

Ratna Sari 72

Used 20+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Persamaan lingkaran yang berpusat di (-1,2) dan melalui titik (3,4) adalah ....

(x1)2+(y+2)2=20\left(x-1\right)^2+\left(y+2\right)^2=20

(x1)2+(y+2)2=20\left(x-1\right)^2+\left(y+2\right)^2=\sqrt{20}

(x+1)2+(y2)2=20\left(x+1\right)^2+\left(y-2\right)^2=20

(x+1)2+(y2)2=20\left(x+1\right)^2+\left(y-2\right)^2=\sqrt{20}

(x+1)2+(y2)2=25\left(x+1\right)^2+\left(y-2\right)^2=25

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Persamaan lingkaran yang berpusat di titik O(0,0) dan melalui titik (2,-3)

x2+y2=13x^2+y^2=13

x2+y2=16x^2+y^2=16

x2+y2=25x^2+y^2=25

x2y2=13x^2-y^2=13

x2y2=16x^2-y^2=16

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 Diketahui lingkaran (x+2)2+(yb)2=8\left(x+2\right)^2+\left(y-b\right)^2=8 melalui titik (-4,4). Pusat lingkaran adalah ....

(2,0)

(-2,0)

(2,2)

(-2,2)

(2,4)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Pusat dan jari-jari lingkaran yang persamaannya  (x+6)2+(y5)2=64\left(x+6\right)^2+\left(y-5\right)^2=64  adalah ....

Pusat (-5,6) dan jari-jari 8

Pusat (6,-5) dan jari-jari 64

Pusat (6,-5) dan jari-jari 8

Pusat (-6,5) dan jari-jari 64

Pusat (-6,5) dan jari-jari 8

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Persamaan lingkaran berpusat di (-2,3) berjari-jari 4 adalah ....

(x2)2+(y+3)2=4\left(x-2\right)^2+\left(y+3\right)^2=4

(x+2)2+(y3)2=4\left(x+2\right)^2+\left(y-3\right)^2=4

(x2)2+(y+3)2=16\left(x-2\right)^2+\left(y+3\right)^2=16

(x+2)2+(y3)2=16\left(x+2\right)^2+\left(y-3\right)^2=16

(x+2)2+(y3)2=36\left(x+2\right)^2+\left(y-3\right)^2=36

6.

MULTIPLE CHOICE QUESTION

30 sec • 12 pts

Petugas pemantau gunung berapi menyatakan bahwa orang-orang yang berada dibawah radius 7 km dari gunung berapi yang berada di koordinat (2, 3) harus mengungsi untuk menghindari akibat letusan. Apabila dibuat peta, maka persamaan lingkaran yang menyatakan batas maksimal daerah rawan bencana adalah ....

x2+y24x6y+6=0x^2+y^2-4x-6y+6=0

x2+y24x6y36=0x^2+y^2-4x-6y-36=0

x2+y2+4x+6y36=0x^2+y^2+4x+6y-36=0

x2+y2+4x+6y+62=0x^2+y^2+4x+6y+62=0

 x2+y24x6y+62=0x^2+y^2-4x-6y+62=0  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Soal UN 2013
Persamaan lingkaran yang berpusat pada titik  (4,3)\left(4,-3\right)  dan berdiameter 8  adalah....

 x2+y28x+6y=0x^2+y^2-8x+6y=0  

 x2+y2+8x6y+16=0x^2+y^2+8x-6y+16=0  

 x2+y28x+6y+16=0x^2+y^2-8x+6y+16=0  

 x2+y2+8x6y+9=0x^2+y^2+8x-6y+9=0  

 x2+y28x+6y+9=0x^2+y^2-8x+6y+9=0  

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