Geometria no espaço

Geometria no espaço

10th - 12th Grade

20 Qs

quiz-placeholder

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Geometria no espaço

Geometria no espaço

Assessment

Quiz

Mathematics

10th - 12th Grade

Practice Problem

Hard

Created by

Ana Machado

Used 64+ times

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20 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

 2x+2y+z=42x+2y+z=4  é a equação cartesiana do plano  ACDACD 

A medida do volume do paralelepípedo é igual a: 

 1616  

 88  

 828\sqrt{2}  

 44  

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Qual é o ponto médio do segmento de reta de extremos A(0;-6;2) e B(4;8;-2)?

(2;1;0)

(4;7;4)

(2;2;0)

(1;2;0)

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Qual é a equação do plano que passa no ponto A(2; 3; 8) e é paralelo a xOy?

x=8

z=8

x=2

y=1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Num referencial o.n. Oxyz, considere os pontos A (3, 2, 1) e B (3, –4, 2k), com k um número real.
Quais os valores de k, tal que a distância de A a B é 10.

 k=72k=92k=-\frac{7}{2}\vee k=\frac{9}{2}  

 k=92k=72k=-\frac{9}{2}\vee k=\frac{7}{2} 

 k=162k=1+62k=\frac{1-\sqrt{6}}{2}\vee k=\frac{1+\sqrt{6}}{2}  

Não existem k de modo que a distância entre A e B seja 10

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Num referencial o.n. Oxyz, considere os pontos A (3,2,1) e B (2,–1,3).

Qual a equação da superfície esférica de centro B e que contém A.

(x2)2+(y+1)2+(z3)2=14\left(x-2\right)^2+\left(y+1\right)^2+\left(z-3\right)^2=14

(x3)2+(y2)2+(z1)2=14\left(x-3\right)^2+\left(y-2\right)^2+\left(z-1\right)^2=14

(x2)2+(y+1)2+(z3)2=7\left(x-2\right)^2+\left(y+1\right)^2+\left(z-3\right)^2=7

(x3)2+(y2)2+(z1)2=7\left(x-3\right)^2+\left(y-2\right)^2+\left(z-1\right)^2=7

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Qual a condição que defina a esfera tangente ao plano yOz e de centro no ponto de coordenadas (–3, –1, 5).

(x+3)2+(y+1)2+(z5)29\left(x+3\right)^2+\left(y+1\right)^2+\left(z-5\right)^2\le9

(x+3)2+(y+1)2+(z5)23\left(x+3\right)^2+\left(y+1\right)^2+\left(z-5\right)^2\le3

(x+3)2+(y+1)2+(z5)2=3\left(x+3\right)^2+\left(y+1\right)^2+\left(z-5\right)^2=3

(x+3)2+(y+1)2+(z5)2=9\left(x+3\right)^2+\left(y+1\right)^2+\left(z-5\right)^2=9

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A interseção da superfície esférica de equação reduzida

 x2+y2+z2=25x^2+y^2+z^2=25  
 com o plano de equação cartesiana  y = 3 é uma circunferência. Qual é o centro e o raio?

  

Centro (0, 0, 0) e raio 5

Centro (0, 3, 0) e raio 5

Centro (0, 3, 0) e raio 4

Centro (0, 3, 0) e raio 3

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