Factor x 3 − 27 x^{3\ }-\ 27 x 3 − 2 7

( x − 3 ) ( x 2 + 3 x + 9 ) \left(x-3\right)\left(x^{2\ }+3x+9\right) ( x − 3 ) ( x 2 + 3 x + 9 )

( x + 3 ) ( x 2 + 3 x + 9 ) \left(x+3\right)\left(x^{2\ }+3x+9\right) ( x + 3 ) ( x 2 + 3 x + 9 )

( x − 3 ) ( x 2 − 3 x + 9 ) \left(x-3\right)\left(x^{2\ }-3x+9\right) ( x − 3 ) ( x 2 − 3 x + 9 )

Factor x 3 + 27 x^{3\ }+\ 27 x 3 + 2 7

( x + 3 ) ( x 2 − 3 x + 9 ) \left(x+3\right)\left(x^{2\ }-3x+9\right) ( x + 3 ) ( x 2 − 3 x + 9 )

( x − 3 ) ( x 2 + 3 x + 9 ) \left(x-3\right)\left(x^{2\ }+3x+9\right) ( x − 3 ) ( x 2 + 3 x + 9 )

( x − 3 ) ( x 2 − 3 x + 9 ) \left(x-3\right)\left(x^{2\ }-3x+9\right) ( x − 3 ) ( x 2 − 3 x + 9 )

Factor 8 x 3 + 1 8x^{3\ }+1 8 x 3 + 1

( 2 x + 1 ) ( 4 x 2 − 2 x + 1 ) \left(2x+1\right)\left(4x^{2\ }-2x+1\right) ( 2 x + 1 ) ( 4 x 2 − 2 x + 1 )

( 8 x + 1 ) ( x 2 + x + 1 ) \left(8x+1\right)\left(x^{2\ }+x+1\right) ( 8 x + 1 ) ( x 2 + x + 1 )

( 2 x + 1 ) ( 4 x 2 + x + 1 ) \left(2x+1\right)\left(4x^{2\ }+x+1\right) ( 2 x + 1 ) ( 4 x 2 + x + 1 )

Jason is factoring a "sum of cubes" problem. His first factor is ( x − 5 ) \left(x-5\right) ( x − 5 ) , what is the second factor?

( x 2 + 5 x + 25 ) \left(x^{2\ }+5x\ +25\right) ( x 2 + 5 x + 2 5 )

( x 2 + 5 ) \left(x^{2\ }+\ 5\right) ( x 2 + 5 )

( x 2 + 5 x − 25 ) \left(x^{2\ }+5x\ -25\right) ( x 2 + 5 x − 2 5 )

Factor completely 3 x 3 + x 2 − 27 x − 9 3x^{3\ }+\ x^{2\ }-\ 27x-9 3 x 3 + x 2 − 2 7 x − 9

( x − 3 ) ( x + 3 ) ( 3 x + 1 ) \left(x-3\right)\left(x+3\right)\left(3x+1\right) ( x − 3 ) ( x + 3 ) ( 3 x + 1 )

( x − 3 ) ( x + 3 ) ( 3 x − 1 ) \left(x-3\right)\left(x+3\right)\left(3x-1\right) ( x − 3 ) ( x + 3 ) ( 3 x − 1 )

( x − 3 ) ( x − 3 ) ( 3 x − 1 ) \left(x-3\right)\left(x-3\right)\left(3x-1\right) ( x − 3 ) ( x − 3 ) ( 3 x − 1 )

Factoring Cubics & Quartics

Authored by Joseph Young

Mathematics

9th - 12th Grade

CCSS covered

Used 53+ times

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20 questions

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MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Factor
$x^{3\ }-\ 27$

$\left(x-3\right)\left(x^{2\ }+3x+9\right)$

$\left(x+3\right)\left(x^{2\ }+3x+9\right)$

$\left(x-3\right)\left(x^{2\ }-3x+9\right)$

Tags

CCSS.HSA.APR.C.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Factor
$x^{3\ }+\ 27$

$\left(x-3\right)\left(x^{2\ }+3x+9\right)$

$\left(x+3\right)\left(x^{2\ }-3x+9\right)$

$\left(x-3\right)\left(x^{2\ }-3x+9\right)$

Tags

CCSS.HSA.APR.C.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Factor
$8x^{3\ }+1$

$\left(8x+1\right)\left(x^{2\ }+x+1\right)$

$\left(2x+1\right)\left(4x^{2\ }+x+1\right)$

$\left(2x+1\right)\left(4x^{2\ }-2x+1\right)$

Tags

CCSS.HSA.APR.C.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Factor
$27-8x^{3\ }$

$\left(3-2x\right)\left(9+6x+4x^2\right)$

$\left(3-2x\right)\left(9+6x-4x^2\right)$

$\left(3+2x\right)\left(9+6x+4x^2\right)$

Tags

CCSS.HSA.APR.C.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jason is factoring a "sum of cubes" problem. His first factor is
$\left(x-5\right)$ , what is the second factor?

$\left(x^{2\ }+\ 5\right)$

$\left(x^{2\ }+5x\ +25\right)$

$\left(x^{2\ }+5x\ -25\right)$

Tags

CCSS.HSA.APR.C.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Factor completely
$x^{4\ }-\ 4x^{2\ }+3$

$\left(x-1\right)\left(x+1\right)\left(x^2-3\right)$

$\left(x+1\right)\left(x+1\right)\left(x^2-3\right)$

$\left(x^2+1\right)\left(x^2-3\right)$

Tags

CCSS.HSA.APR.C.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Factor
$x^{4\ }+5x^{2\ }+4$

$\left(x^2-1\right)\left(x^{2\ }+\ 4\right)$

$\left(x^2-1\right)\left(x^{2\ }-\ 4\right)$

$\left(x^2+1\right)\left(x^2+4\right)$

Tags

CCSS.HSA.APR.C.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Factor completely
$x^{4\ }-\ 10x^{2\ }+\ 9$

$\left(x^2+1\right)\left(x^{2\ }+\ 9\right)$

$\left(x+1\right)\left(x-1\right)\left(x^{2\ }+\ 9\right)$

$\left(x+1\right)\left(x-1\right)\left(x-3\right)\left(x+3\right)$

Tags

CCSS.HSA.APR.C.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Factor
$x^{3\ }+\ 4x^{2\ }+\ 9x+36$

$\left(x^2-9\right)\left(x+4\right)$

$\left(x^2+9\right)\left(x+4\right)$

$\left(x+3\right)\left(x-3\right)\left(x+4\right)$

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

10.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Factor
$2x^{3\ }+\ 3x^{2\ }-\ 26x-39$

$\left(x^2-13\right)\left(2x+3\right)$

$\left(x^2+13\right)\left(2x+3\right)$

$\left(x^2-13\right)\left(2x+3\right)\left(2x-3\right)$

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

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Factoring Cubics & Quartics

Factor x3 − 27x^{3\ }-\ 27x3 − 27

Factor x3 + 27x^{3\ }+\ 27x3 + 27

Factor 8x3 +18x^{3\ }+18x3 +1

Factor 27−8x3 27-8x^{3\ }27−8x3

Jason is factoring a "sum of cubes" problem. His first factor is (x−5)\left(x-5\right)(x−5) , what is the second factor?

Factor completely x4 − 4x2 +3x^{4\ }-\ 4x^{2\ }+3x4 − 4x2 +3

Factor x4 +5x2 +4x^{4\ }+5x^{2\ }+4x4 +5x2 +4

Factor completely x4 − 10x2 + 9x^{4\ }-\ 10x^{2\ }+\ 9x4 − 10x2 + 9

Factor x3 + 4x2 + 9x+36x^{3\ }+\ 4x^{2\ }+\ 9x+36x3 + 4x2 + 9x+36

Factor 2x3 + 3x2 − 26x−392x^{3\ }+\ 3x^{2\ }-\ 26x-392x3 + 3x2 − 26x−39

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Discover more resources for Mathematics

Factor
$x^{3\ }-\ 27$

Factor
$x^{3\ }+\ 27$

Factor
$8x^{3\ }+1$

Factor
$27-8x^{3\ }$

Jason is factoring a "sum of cubes" problem. His first factor is
$\left(x-5\right)$ , what is the second factor?

Factor completely
$x^{4\ }-\ 4x^{2\ }+3$

Factor
$x^{4\ }+5x^{2\ }+4$

Factor completely
$x^{4\ }-\ 10x^{2\ }+\ 9$

Factor
$x^{3\ }+\ 4x^{2\ }+\ 9x+36$

Factor
$2x^{3\ }+\ 3x^{2\ }-\ 26x-39$